Bromobenzene is a clear, colorless liquid with a pleasant odor. It is used as a solvent and motor oil additive, and in making other chemicals.
It is a liquid.
The simplest method would be distillation, because bromobenzene has a higher boiling point than chlorobenzene.
When a mixture of carbonmonoxide and HCl is added to Bromobenzene (Gatterman's reaction) a mixture of ortho and para product is obtained which may be separated on the bases of solubilities.
Uses of phenyl in domestic purpose
Beryllium chloride is a nonpolar molecule.
The Bromination of benzene in presence of Ferric chloride produces Bromobenzene the nitration of bromobenzene with dilute nitric acid gives ortho and para products which may be separated by physical means.
When Bromine is mixed with Benzene it becomes bromobenzene.
You can add the sodium hydroxide solution(NaOH). Because NaOH reacts with Br2(Bromine) and generates NaBr. NaBr is dissolved in water while bromobenzene is layered with water, then you could remove Bromine by a liquid separation. The reaction is Br2 + 2NaOH = NaBr + NaBrO + H2O.
A halide ion (I-, Br-, or Cl-) is the most common leaving group of Sn2 reactions
The approximate boiling point of the mixture of water with bromobenzene is between 78 to 93 depending on the intensity and concentrations of mixture compositions. Using the method of steam distillation, the lighter liquid boils off first and the reading recorded. The averages between the first and the subsequent boiling points are recorded to find the common boiling point.
You are trying to make a para compound, so the trick here is to recognize that bromine is an ortho-para director (albeit a weak one) and nitro is a meta director. Therefore, you want to add the bromine first and then the nitro. Doing the reaction in reverse order will result in the meta product. Your reaction pathway is: 1) Benzene + Br2 + FeBr3 => Bromobenzene 2) Bromobenzene + HNO3 + H2SO4 (catalytic) => 1,2 bromonitrobenzene + 1,4 bromonitrobenzene
Not sure what you mean... If you mean 'how is benzene used for the Grignard synthesis of Benzoic Acid,' then the answer is, bromobenzene (C6H5Br) is turned into phenyl Grignard (C6H5MgBr) by the addition of Magnesium in ether, and then dry ice (solid CO2) is added to the reaction mixture to make Benzoate (C6H5COO-), which is the conjugate base of Benzoic Acid. That has got to help you somehow.