When Bromine is mixed with Benzene it becomes bromobenzene.
A catalytic system commonly used for the bromination of toluene is a combination of elemental bromine (Br2) in the presence of a Lewis acid catalyst, such as iron(III) bromide (FeBr3) or aluminum bromide (AlBr3). These catalysts help facilitate the electrophilic aromatic substitution reaction by activating the bromine molecule for attack on the aromatic ring of toluene.
The oxidation number of iron (Fe) in FeBr3 is +3. This is because each bromine atom (Br) has an oxidation number of -1, and since there are three bromine atoms in FeBr3, the overall charge must be balanced by a +3 charge on the iron atom.
Iron bromide is composed of iron (Fe) and bromine (Br) atoms. It can exist in different forms, such as FeBr2 (iron(II) bromide) or FeBr3 (iron(III) bromide), depending on the oxidation state of the iron atom.
* iron (II) bromide * iron bromide * iron dibromide
When iron reacts with bromine, it forms iron (III) bromide, a solid compound that appears as a reddish-brown powder. This reaction is highly exothermic, releasing heat energy. Iron bromide is an important compound used in organic synthesis and as a catalyst in certain reactions.
To convert benzene to p-nitrobromobenzene, you first perform a nitration reaction by treating benzene with a mixture of concentrated nitric acid and sulfuric acid, which introduces a nitro group (-NO2) to produce nitrobenzene. Next, bromination is achieved by reacting nitrobenzene with bromine in the presence of a catalyst, such as iron(III) bromide (FeBr3), ensuring that the bromine is added in the para position relative to the nitro group due to its deactivating and directing effects. This results in the formation of p-nitrobromobenzene.
A catalytic system commonly used for the bromination of toluene is a combination of elemental bromine (Br2) in the presence of a Lewis acid catalyst, such as iron(III) bromide (FeBr3) or aluminum bromide (AlBr3). These catalysts help facilitate the electrophilic aromatic substitution reaction by activating the bromine molecule for attack on the aromatic ring of toluene.
The hydroxyl group in phenol is an activating ortho/para director, but has some slight steric hindrance too ortho position substitution. Therefore, the predominant product of reaction between phenol and bromine will be 4-bromophenol, if reaction conditions are carefully controlled. With excess bromine, di- and tri-bromo phenols will be formed.
The oxidation number of iron (Fe) in FeBr3 is +3. This is because each bromine atom (Br) has an oxidation number of -1, and since there are three bromine atoms in FeBr3, the overall charge must be balanced by a +3 charge on the iron atom.
The chemical formula for Iron(III) bromide is FeBr3. It consists of one iron atom bonded to three bromine atoms.
Iron and bromine will form iron(III) bromide, which has the chemical formula FeBr3.
Iron bromide is composed of iron (Fe) and bromine (Br) atoms. It can exist in different forms, such as FeBr2 (iron(II) bromide) or FeBr3 (iron(III) bromide), depending on the oxidation state of the iron atom.
* iron (II) bromide * iron bromide * iron dibromide
When iron reacts with bromine, it forms iron (III) bromide, a solid compound that appears as a reddish-brown powder. This reaction is highly exothermic, releasing heat energy. Iron bromide is an important compound used in organic synthesis and as a catalyst in certain reactions.
The mechanisms involve simple aromatic electrophilic substitutions. In making this compound, we simply nitrate benzene, then reduce it down with a reducing agent such as LiAlH4 in ether then water. Next, we must protect the highly reactive amino group with acetyl chloride. Then, simply brominate with an FeBr3 catalyst...and you have the compound in high yield. Acidification would also give a nice yield of p-bromoaniline. Dr Jim Romano CEO Orgoman.com and Romano Scientific, New York
the answer to your riddle would have to be fe + br2 --> febr3 --------[[8]]--------------[[8]]-----------------[[O]] police car chase
You are trying to make a para compound, so the trick here is to recognize that bromine is an ortho-para director (albeit a weak one) and nitro is a meta director. Therefore, you want to add the bromine first and then the nitro. Doing the reaction in reverse order will result in the meta product. Your reaction pathway is: 1) Benzene + Br2 + FeBr3 => Bromobenzene 2) Bromobenzene + HNO3 + H2SO4 (catalytic) => 1,2 bromonitrobenzene + 1,4 bromonitrobenzene