GSM (Global System for Mobile) is an international standard for mobile phones.
As per Newton's Law of gravitation F = G * M * m/R^2 But also F = mg Thus, mg = G * M * m/R^2. In this equation m and m will cancel out to get the final result as: g = G * M/R^2.
Yes. Every body that is falling, (if there is no other force then the gravity force) will fall in constant acceleration. Mass does not affect the acceleration of the body. According to Newton's second law: F=m*a m*g=m*a g=a F= Force m= mass a= acceleration g= gravity acceleration m*g= the force of gravity
G=9.80 m/s² , w=648n, W=mg m=w/g m=648/9.8 M=66.12 kg
pe = m*g*h where m = mass, g = force of gravity and h = height
Because the acceleration due to earth (gravitation) dose not depends on the mass of falling object & it's constant for deferent masses :F= (G M m) / d2 …(1)F = ma = mg ...(2)mg = (G M m) / d2g = (G M) / d2 …(3)Where F is The force of gravity , G is gravity constant , M is the mass of earth , m is the mass of the object , d is the distance between earth & the object , a is acceleration and g is gravitationfrom equation 3 since (G) and (M) are constant it's clear that (g) depends only on the distance (d) between Erath and the object and do not depend on the mass of falling object.
As per Newton's Law of gravitation F = G * M * m/R^2 But also F = mg Thus, mg = G * M * m/R^2. In this equation m and m will cancel out to get the final result as: g = G * M/R^2.
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