Theoretical= calculated
Theoretical yield of a reaction is the yield measured by
Theoretical work whereas actual yield is the yield obtained by actual reaction its always less than theoretical yield due to a number of factors such as impurities in reactants side reactions and so on
Voltage is electrical pressure, in joules per coulomb. One volt across one ohm will yield a current of one ampere, which is coulombs per second. One volt, producing one ampere, will yield one watt, which is joules per second.
Yes it can if it's connected in a push pull reconfiguration
Ohms is a unit of resistance. Amps is a measure of current. They are related by Ohm's Law where Voltage = Current x Resistance. In your example Resistance = 100 x 10 to the 6th power So V in Micro volts over 100 would yield current expressed as micro amps. So if you had 100 volts you would have 1 micro amp.
Assuming the zero state output of the DAC is 0 volts, then 4095 steps of 8mv would yield a full scale output of 32.76 volts. The resolution is one part in 4096, or 2.44 percent. An input of 010101101101 is 1389. Multiply that by 8mv, and you get 11.11 volts.
A clipper is a device designed to prevent the output of a circuit from exceeding a predetermined voltage level without distorting the remaining part of the applied waveform.A clipping circuit consists of linear elements like resistors and non-linear elements like junction diodes or transistors but it does not contain energy-storage elements like capacitors. Clipping circuits are used to select for purposes of transmission, that part of a signal wave form which lies above or below a certain reference voltage level.In half wave rectification of a single-phase supply, either the positive or negative half of the AC wave is passed, while the other half is blocked. Because only one half of the input waveform reaches the output, mean voltage is lower. Half-wave rectification requires a single diode in a single-phase supply , or three in a three-phase supply. Rectifiers yield a unidirectional but pulsating direct current; half-wave rectifiers produce far more ripple than full-wave rectifiers, and much more filtering is needed to eliminate harmonics of the AC frequency from the output.Half-wave rectifierThe no-load output DC voltage of an ideal half wave rectifier for a sinusoidal input voltage is:Where:Vdc, Vav - the DC or average output voltage,Vpeak, the peak value of the phase input voltages,Vrms, the root-mean-square value of output voltage.
The actual yield is less than the theoretical yield.
Percent yield = Actual Yield / Theoretical Yield * 100 hope that helps :)
The percentage yield is the Actual Yield divided by the Theoretical Yield, all multiplied by 100. Percentage = [(Actual)/(Theoretical)] x 100
Not at all. Just be consistent with the units of both actual and theoretical yield.
If actual yield is higher than theoretical yield then it means the required products contains impurities.
The percent yield is the ratio of the actual yield to the theoretical yield. A mole ratio is a conversion factor derived from the coefficient of a balanced chemical equation interpreted in terms of moles.
If this is the actual yield, real amount produced, then you need the theoretical yield to find the percent yield. % yield = (actual yield / theoretical yield) x 100
No, competing side reaction is a reson why the actual yield is more than the theoretical yield.
%yield = actual/theoretical x 100 = 12.01/23.54 x 100 = 51.02 %
actual yield multiply by 100 = % yield theoretical yield
Percentage yield = (Actual yield / Theoretical yield) x 100% The percentage yield for a reaction is a value between 0 to 100 percent.
# Determine the limiting reagent; # Calculate the expected yield if the reaction goes to 100% completion. # Divide the actual yield by the expected yield and multiply by 100. The result is percentage yield.