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Ohms is a unit of resistance. Amps is a measure of current. They are related by Ohm's Law where Voltage = Current x Resistance.
In your example Resistance = 100 x 10 to the 6th power So V in Micro volts over 100 would yield current expressed as micro amps.
So if you had 100 volts you would have 1 micro amp.
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Do the rules of 0hm's lawas learned in dc theory also apply to ac circuits?
Yes, circuit theory works equally well for ac or dc. But ac circuits also allow capacitance and inductance in addition to resistance, and this is allowed for by using complex numbers for the impedance of the components. So if the supply voltage is 100 v and there is a resistor of 4 ohms in series with a perfect inductor with a reactance of 3 ohms across the supply, the total impedance is 4+j3 ohms, so the current is 100/(4+j3) ohms, which is 20 amps but its total description it 16-j12 amps, showing that the current lags the voltage by 36.87 degrees of phase.
A 5 ohm resistor a 20 ohm resistor and a 25 ohm resistor are all connected in series to a 100 volt power source What is the current running through the circuit?
To find the current running through the circuit, you need to use Ohm's Law, which states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them. You can use the following formula to calculate the current: I = V / R Where I is the current, V is the voltage, and R is the resistance. In this case, the total resistance of the circuit is the sum of the individual resistances, which is 5 ohms + 20 ohms + 25 ohms = 50 ohms. Therefore, the current flowing through the circuit is: I = 100 volts / 50 ohms = 2 amps.
How do you converts ohms to dB?
You must find a resistance value for 0 dB as reference. If 1 Ohm = 0 dB then 10 ohms = 20 dB and 100 ohms = 40 dB.
What is the power dissipated a resistor with a current of 0.02 amps and a resistance of 1000 ohms?
P = I^2 x R] P = 0.2^2 x 100 P = 4 W
How do you determine shorted resistor?
A short circuit is an unexpected path of zero resistance between two nodes in a circuit. If you measure the resistance of a resistor, and find that is has zero ohms, but the resistor is supposed to be somthing else, such as 100 ohms, then you can conclude that the resistor is shorted. Keep in mind that the precision of the measurement might be critical. If the resistor is supposed to be 100 ohms, but you get zero ohms, then the answer is easy. If the resistor is 0.001 ohms, but you get zero ohms, then you have to consider the precision of the measurement, the resistance of the wires, etc.
How do you calculate ohms?
Very basically, simply divide the voltage by the amperage. Thsi is not for calculating Ohms of resistance, just Ohms. For example, a 9 volt battery that delivers 3 amps has 3 ohms. To calculate ohms of resistance we use the ohms law. This measures the difference in current flow in amps (amps/current is amount or volume of flow, volts is power pushing that current, sort of) and voltage. For instance, measure the amps and voltage at the source and record the ohms. Then record the same at the end point the difference in ohms is ohms of resistance. So, if we measure 10 volts and 2 amps at the source we have 5 ohms. at the end point we have 8 volts and 1 amp we have 8 ohms. therefore we have 13 ohms of resistance. 1 Determine current. Current is the flow of electricity measured in amps. For example a current has four amps in the circuit. 2 Determine voltage. Voltage is the difference in electrical potential from two points, measured in volts. For example, there is two-hundred volts in a circuit. 3 Divide voltage by current to calculate resistance. Resistance is measured in ohms. In the example, two-hundred volts divided by four amps equals fifty ohms. 4 To get ohms of resistance, measure the end point. at the endpoint we have 100 volts and 2 amps=50 ohms. therefore we have 100 ohms of resistance
Can you Convert 4.5 amps to mA?
Multiple by 100 - 4.5 X 100 = 4500mA
How do you convert a 50 micro-amp DC meter to a 100 milli-amp meter?
with a resistor 300K in series with the 50 micro amperes DC meter
What will be the voltage drop across each what resistors A 160 Ohms B 100 Ohms C 82 Ohms D 120 Ohms.?
Ohm's Law requires you know two of three parameters to calculate the third. Volts = Amps x Ohms You need to know current flowing through resistance to calculate voltage drop.
A electric heater works by passing a current of 100 A through a coiled metal wire making it red hot if the resistance of the wire is 1.1 ohms what voltage must be applied to it?
Volts = Amps * ohms 110 = 100*1.1 Thus the voltage was 110 Volts.
You have 4 ohms subwoofer which amplifier is applicable?
Take a good 100 watt amplifier. Don't look for one with an output impedance of 4 ohms. All amps have output impedances of less than 0.5 ohms, because we use voltage bridging and not power matching.
How multimeter work?
A multimeter is used to measure three electrical characteristics in circuits: Voltage Current and Resistance. AC and DC voltage and current can be measured. These three are related by Ohms law: Voltage ( in volts) = Current (in amps) times Resistance (in ohms) see http://en.wikipedia.org/wiki/Ohm%27s_law The main component in a multimeter is a micro amp meter. A hair thin wire is wound around an iron core on a pivot and with in a permanent magnetic field. When current flows through the coil it produces a magnetic force proportional to the current that causes the coil to move on the pivot against the permanent magnetic field. A pointer is attached to the coil and it move past the meter scale. The coil has some resistance 50 Ohms. If one volt of direct current is applied the 200 Milli amps of that current would turn the coil with so much force that it would pin the needle or break the mechanism. Typical micro ammeters are limited to 50 micro amps maximum. In a parallel circuit current divides inversely proportionally to the resistance. If a wire of 0.5 ohms is placed in parallel with the meter coil then 99% of the current will go through the wire (shunt) and 1% will go through the coil. The meter range would become 5000 micro amps or 5 Milli amps. If the shunt was made to .05 ohms the range would be 50 milli amps. Instead of a shunt a resistor of 4,950 ohms is wired in series with the coil. Now the total resistance is 5,000 ohms if 100 volts is placed across the meter and shunt the meter will only show 50 micro amps.
A galvanometer of resistance 50 ohms is shunted with a wire of 10 ohmsCalculate the current through the galvanometer when the current in the circuit is 12 amps?
If this is a homework related question, you really should consider trying to solve it yourself before looking at this answer. Otherwise, the value of the lesson, and the reinforcement provided by the assignment, will be lost to you. To calculate the current flow in one element of a parallel circuit, knowing the resistance of each element, consider the net resistance first. Two resistors in parallel, R1 and R2, have a net resistance of R1R2/(R1+R2). For 50 ohms and 10 ohms, this is 8.333 ohms. Now, consider the voltage across the resistors. By Ohm's law, voltage is current times resistance. For 12 amps and 8.333 ohms, you get 100 volts. Now, consider the current through one resistor, By Ohm's law, current is voltage divided by resistance. For 100 volts and 50 ohms, you get 2 amps. All of that said, now to the easier method... Resistors in parallel form a current divider, just like resistors in series form a voltage divider. You have two resistors, 10 ohms and 50 ohms, with 12 amps going through them. The current through the 50 ohm resistor is the ratio of the other resistor divided by the sum of the two resistors. This is 12 amps times 10 / (10 + 50), or 12 amps times 1 / 6, or 2 amps.
What size of wire is required for 20 amps 220v over 100 ft?
12 AWG should be fine since resistance of wire is only about .16 ohms per 100 ft.
In a simple series circuit where you have a 9V supply connected to a negative terminal with about 2 amps of current flowing you have a resistor of 100 ohms in between the 9V supply and 0V?
If a 9V supply is connected to a 100-ohm resistor, then the current is not 2 Amps,or even close to it.I = E/R = 9/100 = 0.09 amp.
How do you covert watts to amps?
Watts = current x volts, so you have to multiply Kw value by 1000 to get watts, then divide by the applied voltage. examples. 2Kw kettle (U.S) current = 2 x1000 divided by 120, or 16.7 amps 2Kw kettle (UK) current = 2 x1000 divided by 240 or 8.35 amps 100 watt car amplifier current = 100 divided by 12 volts = 8.5amps
How much current will be drawn by a120v series circut containing a 100 ohm load and a 50 ohm load?
If they are in series, the total resistance is 150 ohms so the current is 120/150 amps. If they are in parallel, the current is 120/100 plus 120/50 amps.
