To find the current running through the circuit, you need to use Ohm's Law, which states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them.
You can use the following formula to calculate the current:
I = V / R
Where I is the current, V is the voltage, and R is the resistance.
In this case, the total resistance of the circuit is the sum of the individual resistances, which is 5 ohms + 20 ohms + 25 ohms = 50 ohms.
Therefore, the current flowing through the circuit is:
I = 100 volts / 50 ohms = 2 amps.
Resistors do that when there's a current running through them.
Circuit breakers are in place to prevent an over-current condition. When too much current is passed through a wire, it overheats and can result in fire. The circuit breaker is just doing its job when it turns off a circuit in that kind of condition. Too many appliances running simply means too much current on a circuit.
What is the voltage drop running through resistor one
Yes, a sump pump can be connected to a generator to make it operate. Keep in mind that the starting current of the pump motor could be 300% of the running current and the sizing of the generator should take this into account. If you are looking for the sump pump using a mechanical connection it will connect to the engine and not to the generator.
An open-circuit test is done with the transformer running at its rated voltage but with no load. This measures the power lost in the magnetic core. (IR Losses) A short-circuit test is done with the transformer running at its full rated current in all windings but at a low voltage. The secondary is shorted and the primary voltage is adjusted to give the rated current. This measures the power lost in the copper windings. (Copper losses)
E/R=I. 100/50=2 amps.
To calculate the current running through the 60 ohm resistor in a parallel circuit, you first need to find the total resistance of the circuit. For a parallel circuit, the reciprocal of the total resistance (1/RT) is equal to the sum of the reciprocals of the individual resistances (1/R1 + 1/R2 + 1/R3). Once you find the total resistance, you can use Ohm's Law (I = V/R) to calculate the current running through the 60 ohm resistor.
What is the current running through resistor four?1 amps..!What is the current running through resistor one? 3 amps...!What is the current running through resistor three? 2amps..!What is the current running through resistor five? 3 amps..!What is the voltage drop running through resistor five? 45 volts...!What is the equivalent resistance through the parallel portion of the circuit? 6 ohmsAnswerA resistor is a conductor, albeit one with a higher resistance than a length of wire, so current passes through it without any problem. The magnitude of the current will, of course, be somewhat lower because of the additional resistance.
To calculate the total current in the circuit, you first need to find the total resistance by using the formula for resistors in parallel: 1/Total Resistance = 1/120 + 1/60 + 1/40. Once you have the total resistance, you can use Ohm's Law: Current = Voltage / Total Resistance. Finally, to find the current running through the 40 ohm resistor, you divide the total current by the resistance of the 40 ohm resistor.
1amp
To find the current through the 40 ohm resistor, first calculate the total resistance of the parallel circuit: 1/Rt = 1/120 + 1/60 + 1/40. Then, calculate the total current using Ohm's Law, I = V/Rt. Finally, use the current divider rule to find the current passing through the 40 ohm resistor.
If they're in parallel, then each resistor acts as if it were the only one,and the presence of any others is irrelevant.The current through the 60-ohm resistor is I = E/R = (120/60) = 2 amperes.
6
If they're in parallel, then the resistors have no effect on each other. The current through each one is the same as it would be if the others were not there at all. The current through the 120Ω resistor is 120 volts/120Ω = 1 Ampere. The 60Ω and the 40Ω are red herring resistors.
Three
The current through the 40-ohm resistor is ( E / R ) = (120 / 40) = 3 amperes.The current through the 40-ohm resistor doesn't depend on the 120-ohm resistor. It's the samewhether the 120-ohm is there or not. It would also be the same if there were any other resistor,with any other resistance, connected in place of the 120-ohm resistor. It would also be the sameif there were 3,000 more resistors in parallel, with all different values of resistance (as long asthe whole conglomeration didn't exceed the capabilities of the power source).
I'm having some trouble focusing in on the schematic of the circuit.