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If a 9V supply is connected to a 100-ohm resistor, then the current is not 2 Amps,

or even close to it.

I = E/R = 9/100 = 0.09 amp.

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Q: In a simple series circuit where you have a 9V supply connected to a negative terminal with about 2 amps of current flowing you have a resistor of 100 ohms in between the 9V supply and 0V?
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