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+5 for each N, -2 for each O, in N2O5
The oxidation number of a free element is zero. However, the oxidation number of elements (e.g. iodine) in compounds will not be zero. The actual oxidation number/state can be deduced if the chemical formula of the compound is given.
-1 for Chlorine, +1 for Iodine
-2 for Oxygen, +2 for Iodine
3.
IO2 is the chemical formula of iodine dioxide.
zero for iodine
+5 for each N, -2 for each O, in N2O5
+5. F is always -1
The oxidation number of a free element is zero. However, the oxidation number of elements (e.g. iodine) in compounds will not be zero. The actual oxidation number/state can be deduced if the chemical formula of the compound is given.
-1 for Chlorine, +1 for Iodine
-2 for Oxygen, +2 for Iodine
3.
As it forms the I- ion froming an octet its most likely oxidation number is -1
+5. The formula of phosphorus pentoxe is P2O5. (It should be called diphosphorus pentoxide but historically they got it wrong). O is -2 so P has to be +5
Oxidation states of elements in Iodate anion: Iodine = +5 Oxygen = -2
Iodine +5, O -2.