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You can find the major axis, 0.5+31.5 or 32 AU. The semimajor axis is half that, 16 AU. Then you can use Keplers 3rd law to calculate the period, which is 161.5 or 64 years.
This is known as Keplers 2nd Law of Planetary Motion. It states that line drawn between a planet and the sun sweeps out equal areas during equal time intervals.
Kepler's first law says Neptune has an elliptical orbit with the Sun at one focus. The same goes for the other planets.
... when it is closest to the Sun. (Kepler's Second Law)... when it is closest to the Sun. (Kepler's Second Law)... when it is closest to the Sun. (Kepler's Second Law)... when it is closest to the Sun. (Kepler's Second Law)
According to Kepler's second law, Jupiter will be traveling most slowly around the Sun when at aphelion.
It is the third law
You can find the major axis, 0.5+31.5 or 32 AU. The semimajor axis is half that, 16 AU. Then you can use Keplers 3rd law to calculate the period, which is 161.5 or 64 years.
This is known as Keplers 2nd Law of Planetary Motion. It states that line drawn between a planet and the sun sweeps out equal areas during equal time intervals.
Kepler's second law the law of equal areas.
Kepler's first law says Neptune has an elliptical orbit with the Sun at one focus. The same goes for the other planets.
... when it is closest to the Sun. (Kepler's Second Law)... when it is closest to the Sun. (Kepler's Second Law)... when it is closest to the Sun. (Kepler's Second Law)... when it is closest to the Sun. (Kepler's Second Law)
this corresponds to Keplers 3rd law of planetary motion P ^2 = R^3 p Squared is equal to the period of revolution, in years r is equal to the distance from the sun in astronomical units. this is a simple version of the principle, Newton modified it.
It is Kepler's first law which says the planet moves in an ellipse with the Sun occupying one focus and the other focus is vacant.
According to Kepler's second law, Jupiter will be traveling most slowly around the Sun when at aphelion.
Use Kepler's Third Law. The simplest form of that Law is P2 = D3 Where P is the orbital period of the planet in Earth years and D is the average distance from the Sun in Astronomical Units. The question says Jupiter is 5.2 AU from the Sun. 5.2 cubed is 140.608 So, the period of revolution for Jupiter is the square root of that, which is about 11.86. So, the answer is about 11.86 Earth years.
Newton derived Keplars findings from Newton's Theory of Gravity. Thus, newton 'explained' the basis for Keplars findings and extended them.
Using Kepler's 3rd(?) law, the duration of a planet's orbit squared is the same as the planet's distance from the Sun cubed . Jupiter is (on average) 5.2 times further from the Sun than our planet, so we say 5.2 AU(Astronomical Units- distance from Earth to Sun) Using Keplers Law Length of Jovian Orbit Squared = 5.2 cubed (5.2x5.2x5.2) = 140.608 So to get the Jovian Orbital Duration we need the square root of 140.608 Which is 11.858. That's roughly 12 years