carried on the x chromosome
Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.
If the father's Rh allele pattern is +-, he would be Rh+ but could still pass on the - allele to the child. Combined with an O- allele from the mother, the result would be an O- child.
Since the mother would be considered a carrier, the gene will be produced in the offspring. the son will receive that gene and will be colorblind.
Suppose letter T represent an allele for tallness in an organism, its homozygous combination would be TT and heterozygous combination would be Tt.
Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
We know that if a father is colorblind and the mother is neither colorblind nor a carrier, then the sons will not be colorblind. So, using logic, that means that the father can't cause a son to become colorblind. Process of elimination would point towards whenever a son is colorblind that it comes from the mother. A diagram explaining how colorblindness is inherited can be viewed in the related links.
Yes. Both parents have an A allele and a B allele. Each parent can only pass on one of his/her two alleles. If each parent passes an A allele to the child, then the child will have group A blood. If at least one parent passes on an Rh positive allele to the child, then the child would also be type Rh positive. So these two parents could have an A positive child.
Color Blindness is x-linked recessive. Therefore, it could not be heterozygous; the daughter would not be colorblind, but rather have normal vision.
If both parents are O+ve, it means they have i allele, which is a recessive allele. For a person to have A+ve blood group, IA allele should be present. But in case of both parents being O+ve, there is no possibility that either of the parents carry the IA allele since it is a dominant allele. Thus the child would have to be O+ve.
Nobody really knows, people say cats are colorblind when they are not really. So I would say "No." donkeys are not colorblind
it is because the parents each were heterozyous dominant. meaning each of them had a dominant allele and a recessive allele. the dominant allele would be the curly hair, and the recessive allele would be the straight hair. There would be a 1/4 chance that the child would have curly hair, and a 3/4 chance that they would have curly hair. Say that the Curly hair allele was H and the straight hair allele was h. In order for the parents to have curly hair, they would either have to have an HH gamete or an Hh gamete. Seeing as though the child came out with curley hair, both parents would have to have an Hh gamete. In order to find out the probability, you multiply the parents gametes. (Hh)(Hh). This will give you HH, Hh, Hh, hh. seeing has three of the gametes have the dominant allele, this child will have curly hair, and one is a homozygous recessive, so it will turn out with straight hair.