Three different oxidation values:
here is a link to the answer
http://www.sciencegeek.net/APchemistry/APpdfs/charges.pdf
It can either be 2+ as in SnCl2 or 4+ as in SnO2. In general the +4 oxidation state is favoured over the +2 for Sn, whilst the reverse is true for Pb.
Chlorine ions are most commonly negative, as chlorine atoms tend to gain an electron (negative charge) than lose one. This gives them a negative charge.
Tin(IV) is tetravalent.
Tin ions are Sn2+ and Sn4+.
positive
positive
+50
*Tin Sulfate* NO! This is WRONG!SnS2 is Tin(IV) Sulfide, not Tin SulfateThe (IV) means that Tin has a 4+ charge (can be Tin(II) with a 2+ charge or Tin(IV))Sulfur has a 2- charge, so it takes 2 Sulfur ions to balance out the chargesso you have 1 Tin Ion with a charge of 4+ and 2 Sulfur Ions with charges of 2+put them together and it makes SnS2Sulfate is a polyatomic ion with the formula SO4 with a 2- charge, so the formula for Tin Sulfate would be Sn(SO4)2
Sn(CrO4)2 Tin 4 means that the tin is a cation with a +4 charge. Chromate is a polyatomic ion with the formula (CrO4)-2. Since the tin ion has a +4 charge in this case, and the chromate ion has a -2 charge, there is a 1:2 ratio of tin ions to chromate ions.
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
The systematic name of this ionic compound is Tin(IV) Selenide.
Tin (IV) nitrideTin(IV) Nitride.
*Tin Sulfate* NO! This is WRONG!SnS2 is Tin(IV) Sulfide, not Tin SulfateThe (IV) means that Tin has a 4+ charge (can be Tin(II) with a 2+ charge or Tin(IV))Sulfur has a 2- charge, so it takes 2 Sulfur ions to balance out the chargesso you have 1 Tin Ion with a charge of 4+ and 2 Sulfur Ions with charges of 2+put them together and it makes SnS2Sulfate is a polyatomic ion with the formula SO4 with a 2- charge, so the formula for Tin Sulfate would be Sn(SO4)2
First we have to start by determining what charge does Sn have to form this compound. Remember that Fluorine has -1 charge (F-1) and there are 4 of them. That means that Sn must have a +4 charge; therefore, the compound would be called: Tin(IV) fluoride or Stannic fluoride.
Sn(CrO4)2 Tin 4 means that the tin is a cation with a +4 charge. Chromate is a polyatomic ion with the formula (CrO4)-2. Since the tin ion has a +4 charge in this case, and the chromate ion has a -2 charge, there is a 1:2 ratio of tin ions to chromate ions.
The Answer To Your Question Is.... tin (IV) oxide
It is SnO2Why? Because:Tin has a charge of 4 and Oxygen has a charge of 2. Their charges are switched to make a compound; therefore, the chemical formula would be written as Sn2O4. Then, you have to simplify that so it would be written as SnO2.
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
Tin (IV) phosphide
Sn4+ is the symbol for Tin(IV), that is, the element tin with a oxidation state of 4.
The systematic name of this ionic compound is Tin(IV) Selenide.
Tin (II) Bromide.
Tin (IV) nitrideTin(IV) Nitride.
Tin (IV) Chloride