0
What else can I help you with?
What is the ionic compound SnBr4 called?
The ionic compound SnBr4 is called tin (IV) bromide. It consists of tin cations with a +4 charge and bromide anions with a -1 charge.
What is Tin IV?
Tin IV refers to tin in its +4 oxidation state. This means that tin atom has lost four electrons and has a charge of +4. Tin IV compounds are commonly found in tin dioxide (SnO2) and other tin (IV) salts.
What is the formula for tin (IV) chromate?
Sn(CrO4)2 Tin 4 means that the tin is a cation with a +4 charge. Chromate is a polyatomic ion with the formula (CrO4)-2. Since the tin ion has a +4 charge in this case, and the chromate ion has a -2 charge, there is a 1:2 ratio of tin ions to chromate ions.
What is SnS2?
*Tin Sulfate* NO! This is WRONG!SnS2 is Tin(IV) Sulfide, not Tin SulfateThe (IV) means that Tin has a 4+ charge (can be Tin(II) with a 2+ charge or Tin(IV))Sulfur has a 2- charge, so it takes 2 Sulfur ions to balance out the chargesso you have 1 Tin Ion with a charge of 4+ and 2 Sulfur Ions with charges of 2+put them together and it makes SnS2Sulfate is a polyatomic ion with the formula SO4 with a 2- charge, so the formula for Tin Sulfate would be Sn(SO4)2
What is the formula of tin(IV) oxide?
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
What is the ionic compound SnBr4 called?
The ionic compound SnBr4 is called tin (IV) bromide. It consists of tin cations with a +4 charge and bromide anions with a -1 charge.
What is Tin IV?
Tin IV refers to tin in its +4 oxidation state. This means that tin atom has lost four electrons and has a charge of +4. Tin IV compounds are commonly found in tin dioxide (SnO2) and other tin (IV) salts.
What is the correct name for the compound SnF4?
First we have to start by determining what charge does Sn have to form this compound. Remember that Fluorine has -1 charge (F-1) and there are 4 of them. That means that Sn must have a +4 charge; therefore, the compound would be called: Tin(IV) fluoride or Stannic fluoride.
What is the formula for tin (IV) chromate?
Sn(CrO4)2 Tin 4 means that the tin is a cation with a +4 charge. Chromate is a polyatomic ion with the formula (CrO4)-2. Since the tin ion has a +4 charge in this case, and the chromate ion has a -2 charge, there is a 1:2 ratio of tin ions to chromate ions.
What is SnS2?
*Tin Sulfate* NO! This is WRONG!SnS2 is Tin(IV) Sulfide, not Tin SulfateThe (IV) means that Tin has a 4+ charge (can be Tin(II) with a 2+ charge or Tin(IV))Sulfur has a 2- charge, so it takes 2 Sulfur ions to balance out the chargesso you have 1 Tin Ion with a charge of 4+ and 2 Sulfur Ions with charges of 2+put them together and it makes SnS2Sulfate is a polyatomic ion with the formula SO4 with a 2- charge, so the formula for Tin Sulfate would be Sn(SO4)2
What is the chemical formula for tin IV oxide?
It is SnO2Why? Because:Tin has a charge of 4 and Oxygen has a charge of 2. Their charges are switched to make a compound; therefore, the chemical formula would be written as Sn2O4. Then, you have to simplify that so it would be written as SnO2.
What is the name of SnO4?
The Answer To Your Question Is.... tin (IV) oxide
What is the formula of tin(IV) oxide?
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
What is the correct stock name for snbr4?
The correct stock name for SnBr4 is tin(IV) bromide. In this compound, tin has a +4 oxidation state, indicated by the Roman numeral IV, while bromide ions carry a -1 charge. Therefore, four bromide ions are needed to balance the +4 charge of the tin ion.
What is the compound name for Sn3P4?
Tin (IV) phosphide
Tin IV hydroxide formula?
The formula for tin(IV) hydroxide is Sn(OH)4. Tin(IV) has a 4+ oxidation state, leading to the "IV" in its name. Hydroxide is a polyatomic ion consisting of one oxygen and one hydrogen atom with a 1- charge, hence the formula Sn(OH)4.
What is the charge Sn?
Tin has two ions Sn2+ stannous or tin(II) or Sn4+ stannic ion or tin(IV)
