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What are four different ways of adding 79 plus 19 plus 49 plus 3 and four different ways of subtracting 79 -19 -49 -3 but working out all eight calculations from start to finish in Roman numerals?
Wiki User
∙ 7y ago
The rules as we now know them today governing the Roman numeral system had absolutely nothing to do with the ancient Romans because they were introduced during the Middle Ages but we can glean and extrapolate from historical sources that the Romans would have evaluated the equivalent of the given calculations as in any of the following formats and even more if so required:-
ILXXX+IXX+IL+III = CL => (-1+80)+(-1+20)+(-1+50)+3 = 150
LXXVIIII+XVIIII+XXXXVIIII+III = CL => 79+19+49+3 = 150
ILXXX+XVIIII+IL+III = CL
LXXVIIII+IXX+XXXXVIIII+III = CL
ILXXX-IXX-IL-III = VIII => (-1+80)-(-1+20)-(-1+50)-3 = 8
LXXVIIII-XVIIII-XXXXVIIII-III = VIII => 79-19-49-3 = 8
ILXXX-XVIIII-IL-III = VIII
LXXVIIII-IXX-XXXXVIIII-III = VIII
Note that in arithmetic -(1+20) becomes 1-20 which is -19 and that -(-1+50) becomes 1-50 which is -49
QED
Wiki User
∙ 7y ago
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How would you work out 1776 plus 549 in two different ways and 1776 minus 549 in two different ways but working out all four calculations entirely in Roman numerals with explanations?
Roman numerals are entirely inappropriate for doing such calculations. I believe the people in Roman times did such calculations on an abacus or something similar - which is basically similar to converting them to the Arabic numbers we use. If you really want to do it in Roman numerals - which is basically NOT a good idea - you would have to keep the thousands, hundreds, etc. separate, and handle carry (for addition) and borrowing (for subtraction).
What is 1776 plus 249 added in two different ways and 1776 minus 249 subtracted in two different ways but working out all four calculations in Roman numerals with work shown?
Nowadays 249 when converted into Roman numerals is now considered to be CCXLIX but the ancient Romans probably worked out the required calculations as follows:-MDCCLXXVI+ICCL = MMXXV => 1776+(250-1) = 2025MDCCLXXVI+CCXXXXVIIII = MMXXV => 1776+249 = 2025MDCCLXXVI-ICCL = MDXXVII => 1776-(250-1) = 1527MDCCLXXVI-CCXXXXVIIII = MDXXVII => 1776-249 = 1527For more complicated calculations the Romans would have made use of an abacus calculating device.QED
How would you work out 1776 plus 9 in two different ways and 1776 minus 9 in two different ways but working out all four calculations entirely in Roman numerals with explanations?
When 9 is converted into Roman numerals it is IX which is an abridged version of VIIII and so the required calculations are as follows:-MDCCLXXVI+IX = MDCCLXXXV => 1776+(10-1) = 1785MDCCLXXVI+VIIII = MDCCLXXXV => 1776+9 = 1785MDCCLXXVI-IX = MDCCLXVII => 1776-(10-1) = 1767MDCCLXXVI-VIIII = MDCCLXVII => 1776-9 = 1767Note that in mathematics -(10-1) changes to 1-10QED
What is 1776 plus 444 added in two different ways and 17776 minus 444 subtracted in two different ways but working out all four calculations in Roman numerals?
Both 1776 plus 444 added in two different ways will have sum of MMCCXX = 2220 and both 17,776 minus 444 subtracted in two different ways will have a difference of (XVII)CCCXXXII = 17,332
How would you correctly calculate 52 plus 49 and 52 minus 49 but working out both calculations entirely in Roman numerals with explanations?
The modern way of expressing 49 into Roman numerals is now XLIX but the ancient Romans would have probably worked out the equivalent of 49 on an abacus counting frame as XXXXVIIII and then wrote it out as IL thus expediently working out the required calculations as follows:-LII+IL = CI => 52+(50-1) = 101LII-IL = III => 52-(50-1) = 3Note that in mathematics -(50-1) becomes -50+1 and that if we were to use the longer version of 49 in the above calculations the results would be exactly the same.QED
How would you work out 1776 plus 549 in two different ways and 1776 minus 549 in two different ways but working out all four calculations entirely in Roman numerals with explanations?
Roman numerals are entirely inappropriate for doing such calculations. I believe the people in Roman times did such calculations on an abacus or something similar - which is basically similar to converting them to the Arabic numbers we use. If you really want to do it in Roman numerals - which is basically NOT a good idea - you would have to keep the thousands, hundreds, etc. separate, and handle carry (for addition) and borrowing (for subtraction).
Do you always have to find common denominator when working with fractions?
No. Only if you're adding or subtracting and then only if the denominators are different.
What is 1776 plus 249 added in two different ways and 1776 minus 249 subtracted in two different ways but working out all four calculations in Roman numerals with work shown?
Nowadays 249 when converted into Roman numerals is now considered to be CCXLIX but the ancient Romans probably worked out the required calculations as follows:-MDCCLXXVI+ICCL = MMXXV => 1776+(250-1) = 2025MDCCLXXVI+CCXXXXVIIII = MMXXV => 1776+249 = 2025MDCCLXXVI-ICCL = MDXXVII => 1776-(250-1) = 1527MDCCLXXVI-CCXXXXVIIII = MDXXVII => 1776-249 = 1527For more complicated calculations the Romans would have made use of an abacus calculating device.QED
How would you work out 1776 plus 99 in two different ways and 1776 minus 99 in two different ways but working out all four calculations entirely in Roman numerals?
Not withstanding today's modern notation of Roman numerals in as much that the ancient Romans would have probably worked out the required calculations as follows: MDCCLXXVI+IC = MDCCCLXXV => 1776+(100-1) = 1875 MDCCLXXVI+LXXXXVIIII = MDCCCLXXV => 1776+99 = 1875 MDCCLXXVI-IC = MDCLXXVII => 1776-(100-1) = 1677 MDCCLXXVI-LXXXXVIIII = MDCLXXVII => 1776-99 = 1677
How would you work out 1776 plus 9 in two different ways and 1776 minus 9 in two different ways but working out all four calculations entirely in Roman numerals with explanations?
When 9 is converted into Roman numerals it is IX which is an abridged version of VIIII and so the required calculations are as follows:-MDCCLXXVI+IX = MDCCLXXXV => 1776+(10-1) = 1785MDCCLXXVI+VIIII = MDCCLXXXV => 1776+9 = 1785MDCCLXXVI-IX = MDCCLXVII => 1776-(10-1) = 1767MDCCLXXVI-VIIII = MDCCLXVII => 1776-9 = 1767Note that in mathematics -(10-1) changes to 1-10QED
What is 1776 plus 444 added in two different ways and 17776 minus 444 subtracted in two different ways but working out all four calculations in Roman numerals?
Both 1776 plus 444 added in two different ways will have sum of MMCCXX = 2220 and both 17,776 minus 444 subtracted in two different ways will have a difference of (XVII)CCCXXXII = 17,332
What is 1767 plus 9 added in two different ways and 1767 minus 9 subtracted in two different ways but working out all calculations from start to finish in Roman numerals?
Nowadays we think that the equivalent of 9 in Roman numerals is only IX whereas in fact IX is an abridged version of VIIII in ancient Roman numerals thus facilitating the conversion and calculations of the given Hindu-Arabic numerals into Roman numerals in several ways as follows:- MDCCLXVII+VIIII = MDCCLXXVI => 1767+9 = 1776 MDCCLXVII+IX = MDCCLXXVI => 1767+(-1+10) = 1776 MDCCLXVII-VIIII = MDCCLVIII => 1767-9 = 1758 MDCCLXVII-IX = MDCCLVIII => 1767-(-1+10) = 1758 Note that in mathematics that -(-1+10) is equivalent to +1-10 and so -(-I+X) is equivalent to -VIIII
What is 999 plus 777 added in two different ways and 999 minus 777 but working out all three calculations entirely in Roman numerals?
Nowadays 999 when converted into Roman numerals is now considered to be CMXCIX which does not quite easily lend itself for the purpose of arithmetical operations but the ancient Romans would have probably worked out the given three calculations as follows:-IM+DCCLXXVII = MDCCLXXVI => (1000-1)+777 = 1776DCCCCLXXXXVIIII+DCCLXXVII = MDCCLXXVI => 999+777 = 1776DCCCCLXXXXVIIII-DCCLXXVII = CCXXII => 999-777 = 222QED
What is 1776 plus 249 added in two different ways and 1776 minus 249 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?
Under today's modern rules now governing the Roman numeral system the equivalent of 249 when converted into Roman numerals is now considered to be CCXLIX which does not lend itself quite easily to arithmetical operations but there exist credible evidence to suggest that the ancient Romans would have carried out the requested calculations as follows:-MDCCLXXVI+ICCL = MMXXV => 1776+(250-1) = 2025MDCCLXXVI+CCXXXXVIIII = MMXXV => 1776+249 = 2025MDCCLXXVI-ICCL = MDXXVII => 1776-(250-1) = 1527MDCCLXXVI-CCXXXXVIIII = MDXXVII => 1776-249 = 1527Note that in mathematics -(250-1) becomes -250+1 or as 1-250The above calculations were fairly simple and straight forward to work out but for more complicated calculations the Romans would make use of an abacus calculating device.QED
What are two different ways of adding 1776 to 999 and two different ways of subtracting 999 from 1776 but working out all four calculations from start to finish in Roman numerals?
Not withstanding the rules as we now know them today governing the Roman numeral system, that were introduced during the Middle Ages, inasmuch that the ancient Romans would have probably worked out the given numbers into Roman numerals as in any of the following formats:- MDCCLXXVI+DCCCCLXXXXVIIII = MMDCCLXXV => 1776+999 = 2775 MDCCLXXVI+IM = MMDCCLXXV => 1776+(-1+1000) = 2775 MDCCLXXVI-DCCCCLXXXXVIIII = DCCLXXVII => 1776-999 = 777 MDCCLXXVI-IM = DCCLXXVII => 1776-(-1+1000) = 777 Note: IM is a logical abridged version of DCCCCLXXXXVIIII Note: In mathematics -(-1+1000) becomes +1-1000 Note: The equivalent symbol of zero was never needed in Roman numerals
What is the purpose of the Chinese abacus?
For working out arithmetical calculations
How would you add together 1776 plus 1999 in two different ways and subtract 1776 from 1999 working out all three calculations entirely in Roman numerals?
It is now generally accepted that the modern way of expressing 1999 into Roman numerals is now MCMXCIX but the ancient Romans would have probably worked out the above as follows:- A: MDCCLXXVI+IMM = MMMDCCLXXV => 1776+(2000-1) = 3775 B: MDCCLXXVI+MDCCCCLXXXXVIIII = MMMDCCLXXV => 1776+1999 = 3775 C: MDCCCCLXXXXVIIII-MDCCLXXVI = CCXXIII => 1999-1776 = 223 The above calculations are fairly easy and straightforward but for more complicated calculations the Romans would have used an abacus counting device.
