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What else can I help you with?
Why the array is starting from zero?
By design; it makes the compiler's work easier. 1-based array's addressing-function: Address (array, index) = Address (array) + (index-1)*Elemsize(array) 0-based array's addressing-function: Address (array, index) = Address (array) + index*Elemsize (array)
Why does array index begins with 0 not with 1?
It is because array name implies its address and if you want to access first element of it pointer address logic is as below: Arrays first element address = array base address + 0 Arrays second element address = array base address + 1
What is an array controller?
An array controller is a controller of any array of equivalent hardware components.
How to display the content of memory address stored in an element of an array?
void *array[2]; printf ("array[%d]=%p\n", i, array[i]);
How do you find the address of Three dimenesional array?
let the array be "int a[10][10][10];" the address of this multidimensional array can be extracted by the following codes in printf statement. 1. printf("%p", &a[0][0][0]); 2. printf("%p",a); "a" gives the base-address of array
Can you change the base address of an array during run time?
If the compiler allocated the array at compile time, or if the array was automatically allocated as a local variable, then no, you cannot change its base address at run time. If you allocated the array at run time from the heap, you can change its base address by allocating a new array, copying the old elements from old to new and deleting the old array.
What is the base address of an array in c program?
the address of variable (pointer) that contains array
What are array of string pointers?
An array of pointers to string would contain, per array position, a number dictating which memory address holds the string data. For example, position [0] in an array would contain a memory address. This memory address can be de-referenced to obtain the actual information held within that memory address.
Are construct and array equivalent in c?
No.
How is an array name interpretedwhen it is passed to a function?
An array is still an array, regardless of how you pass it into functions. It is still an array-type variable at the beginning of a function. However, the function itself may manipulate the array by "imploding" it into a string with a delimiter, using array values with only specific keys, and such.
What is the relationship between an array and a pointer?
All variable names are an alias for the value stored at the memory address allocated to them. To get the memory address itself, you must use the address of operator (&). The value returned from this can then be stored in a pointer variable.Arrays are different. The array name is an alias for the start address of the array, thus you do not need the address ofoperator to obtain the memory address (although you can if you want to). This means that when you pass an array name to a function, you pass the memory address of the array rather than passing the array itself (which would require the entire array to be copied, which is a highly inefficient way to pass an array). In essence, the array is passed by reference rather than by value.Consider the following code. This shows how a primitive variable name differs from the name of an array of primitive variables. The final portion shows how a pointer can be used to achieve the same results you got by accessing the array elements directly from the array name itself. This is in fact how the compiler implements arrays, using pointers, but there's no need to do this in your code. Accessing array elements directly by their index is a programming convenience.#include using namespace std;int main(){int i = 10;cout
Are the expressions 'arr' and ' and arr' are same for an array of integers?
No arr refers to address of array &arr refers address of address of array but compiler treats arr and & arr, so even you place arr and & arr no error only warnings will be displayed.
