No remotely modern motherboard is compatible with an 8086 processor. The old IBM PC clones from the early to mid 1980s would have been the only motherboards to support the 8086.
The 8086/8088 is the general purpose processor. The 8087 is the math co-processor for the 8086/8088.
The Intel 8086 and 8088 motherboards had the system bus speed, which is 5-10 MHz However, the processors for the motherboards had different external data bus widths with the 8088 CPU featuring an 8-bit bus and the 8086 a 16-bit bus.
it primarily running as a 16 bit processor..so it is so called as 8086
The co-processor on an 8086/8088 is the 8087 math co-processor. The motherboard will be designed with an extra socket for the 8087, which then integrates with the 8086/8088 to make a single unified processor.
No. The 8086 has instructions not present in the 8085. The 8086 was marketed as "source compatible" with the 8085, meaning that there was a translator program which could convert assembly language code for the 8085 into assembly language code for the 8086. However, this does not mean that the compiled 8086 assembly code would then run on an 8085; among other things, the 8086 was a true 16-bit processor, as opposed to the 8085 which was an 8-bit processor that supported a few 16-bit operations.
8086 means its a 8 bit processor and 86 is its model number
It was the first Intel 8 bit processor to which followed the 8086, then the 80186, 80286, etc all of which were code compatible and are often referred to simply as x86 family processors.
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Yes, it has 8086-compatible mode, if that's what you mean.
The 8086/8088 processor is a 16 bit processor. In a 16 bit two's complement notation, the maximum number is 0x7FFF, or 32767, while the minimum number is 0x8000, or -32768.
No. The Pentium IV is not an Intel 8086. It is closer to the 80586.
The processor executes a JMP FFFF:0000