it primarily running as a 16 bit processor..so it is so called as 8086
The 8086/8088 is the general purpose processor. The 8087 is the math co-processor for the 8086/8088.
The co-processor on an 8086/8088 is the 8087 math co-processor. The motherboard will be designed with an extra socket for the 8087, which then integrates with the 8086/8088 to make a single unified processor.
8086 means its a 8 bit processor and 86 is its model number
No remotely modern motherboard is compatible with an 8086 processor. The old IBM PC clones from the early to mid 1980s would have been the only motherboards to support the 8086.
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The 8086/8088 processor is a 16 bit processor. In a 16 bit two's complement notation, the maximum number is 0x7FFF, or 32767, while the minimum number is 0x8000, or -32768.
No. The Pentium IV is not an Intel 8086. It is closer to the 80586.
The processor executes a JMP FFFF:0000
x86
No. The 8086 has instructions not present in the 8085. The 8086 was marketed as "source compatible" with the 8085, meaning that there was a translator program which could convert assembly language code for the 8085 into assembly language code for the 8086. However, this does not mean that the compiled 8086 assembly code would then run on an 8085; among other things, the 8086 was a true 16-bit processor, as opposed to the 8085 which was an 8-bit processor that supported a few 16-bit operations.
Somewhat after the 8086, which was somewhat after the 8085. The 8086 was developed between mid 1976 and early 1978, while the 8088 was developed in 1979.
The 8086 is not a co-processor. The 8087 is. The 8087 is intended to be coupled to an 8086/8088 to do math co-processing.