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What are the dimensions of a rectangle that has an area of 77 yds sq and the length is 3 more than twice the width?
Wiki User
∙ 14y ago
Working this out as I go along:
L = 2w +3 and Lw = 77 ie L = 77/w
so 77/w = 2 w + 3
ie 77= 2w^2 + 3w
factors are (2w - 11)(w + 7)
so width is 5.5 and length is 14
Wiki User
∙ 14y ago
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