The numbers of atoms in 0,250 mole sulfur is 1,50553521425.10e22.
64 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S) = 1.2 X 1024 atoms of sulfur ====================
Because the sum of protons, neutrons and electrons masses in sulfur atom is higher than in a carbon atom.
Yes. To find out the mass of a mole of atoms of any given element, see the atomic mass given on the periodic table. A mole of carbon atoms has a mass of 12.011 grams. A mole of sulfur atoms has a mass of 32.06 grams.
Sulfur has relative atomic mass of 32 and oxygen have that of 16. The molar mass of sulfur dioxide is 64 grams per mole. Therefore there is approximately 0.58 moles (37.14/64) of sulfur dioxide in given weight.
1 mole = 6.022e23 atoms 8.25 mole = 4.96815 e 24 atoms
6.022x10^23 (Avogadro's constant)
2.6*10^24
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
48.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 9.01 X 10^23 atoms of sulfur
Full formal set up. 48.096 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S)(1 mole S atoms/6.022 X 1023) = 1.4997 moles of sulfur atoms ---------------------------------------
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
you would have 6.022 x 10^23 atoms (Avogadro's number)
2 mole S8 (8 mole sulfur/1 mole S8)(6.022 X 1023/1 mole sulfur) = 9.6 X 1024 atoms of sulfur --------------------------------------- Same as any atom ratio in a compound, moles of atoms over moles of the compound times Avogadro's number.
72.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.35 X 10^24 atoms of sulfur
32g of Sulfur is a Mole of Sulfur and therefore contains Avogadro's number of atoms of Sulfur. Avogadro's number is 6.023 × 10 to the 23.