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64 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S)
= 1.2 X 1024 atoms of sulfur
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How many atoms are in 25.1 g. S?
25.1
How many atoms of sulfur (S) are in 5 g of sulfur?
5 g of sulfur contain 0,94.10e23 atoms.
What is the mass of 1 mole of MgSO 4?
1 Fe= 55.85 1 S= 32.07 4 O= 64.00 Molar mass= 151.5304
How many atoms are there in 30.4 g of selenium?
78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
How many uranium atoms are there in 6.2 g of pure uranium?
156,86.1020 atoms of uranium in 6,2 g uranium
How many atoms are in 64 g sulfur (s)?
2(6.02*10 23) atoms
How many atoms are in 64 g sulfur?
2(6.02 x 10^23) atoms
How many atoms are in 25.1 g. S?
25.1
How many atoms of sulfur (S) are in 5 g of sulfur?
5 g of sulfur contain 0,94.10e23 atoms.
How many atoms are present in 8g of S?
8 g sulfur have 1,5027176187149.1023 atoms.
How many atoms are present in 16g of O and 8g of S?
16 g O x 1 mol/16 g = 1 mole and 1 mole = 6.02x10^23 atoms of O8g S x 1 mol/32 g = 0..25 moles S and then 0..25 moles x 6.02x10^23 atoms/mole = 1.5x10^23 atoms of S, or rounding to 1 significant figure, you have 2x10^23 atoms of S
How many atoms are in (1.00)10-10g Au?
1.00x10^-10 g Au x 1 mole Au/197 g x 6.02x10^23 atoms/mole = 3.06x10^11 atoms
How many atoms are there in 32 g of sulfur?
32 g S * (1 mole S/32 g S) * (6.022*1023 atoms/1 mole S) = 6.022*1023 atomsThere are 6.022*1023 atoms in 32 grams of sulfur.
How many atoms are in .23 g Pb?
The number of atoms of lead is 6,68.10e23.
What is the empirical formula of a compound whose composition by mass is 50 percent sulfur and 50 percent oxygen?
50% of 64 g compound XX = 32, so 32 g S = 1.0 mole S 50% of 64 g compound XX = 32, so 32 g O2 = 1.0 mole O2 or =2.0 mole O atoms Thus it is SO2
What is the mass of 1.20x10 to the 25th atoms of sulfur?
1.20x10^25 atoms S x 1 mole S/6.02x10^23 atoms x 32 g/mole S = 638 g
How many oxygen atoms are indicated on the right side of this balanced chemical equation?
4Cr(s)+3O2(g)→2Cr2O3(g)
