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78.96 g of selenium will have 6.023 x 1023 atoms.
So, 30.4 g of selenium will have 2.32 x 1023 atoms.
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Determine the mass in grams of 5.56x1024 atoms of selenium?
6.023 x 1023 atoms of selenium will weigh 78.96 g So, 5.56 x 1024 atoms of selenium will weigh 728.9 g
How many atoms are there in 61.7 g of selenium?
1 mol of sulfur contains 6.02 x 1023 molecules (avogadro constant). In one molecule of sulfur, S8, there are 8 sulfur atoms. Thus, number of atooms in 7.20 moles of sulfur = 8 x 7.20 x 6.02 x 1023 = 3.47 x 1025 Note: Sulfur does not usually exist in a monatomic form but instead forms cyclic octatomic molecules with molecular formula S8.
What is the molarity of a 5ml solution containing 0.7 micrograms of selenium?
The answer is1.77 * 10-6 M.Solution:.7 ug * (1 g \ 106 ug) This converts our value from micrograms (ug) to grams (g).* (1 mole Selenium \ 78.96 g Selenium) This gives out our # of moles Selenium by using Selenium's molar mass (78.96 g/mol).= 8.87 * 10-9 moles SeleniumDivided by the volume in liters (.005 L)= 1.77 * 10-6 moles Selenium \ 1 L (M)Check:.005 L * (1.77 * 10-6 moles Selenium\ 1 L)= .00000177 moles Selenium* (78.96 g Selenium \ 1 mole Selenium)* (106 ug \ 1 g)~= .7 ug.- Mike
How many atoms of sulfur (S) are in 5 g of sulfur?
5 g of sulfur contain 0,94.10e23 atoms.
How many uranium atoms are there in 6.2 g of pure uranium?
156,86.1020 atoms of uranium in 6,2 g uranium
Determine the mass in grams of 5.56x1024 atoms of selenium?
6.023 x 1023 atoms of selenium will weigh 78.96 g So, 5.56 x 1024 atoms of selenium will weigh 728.9 g
How many atoms are there in 80.7 g of selenium?
Atomic mass Se = 78.96. So, atoms Se in 80.7g would be 80.7 g x 1mol/78.96g x 6.02x10^23atoms/mol = 6.15x10^23 atoms
How many atoms are there in 61.7 g of selenium?
1 mol of sulfur contains 6.02 x 1023 molecules (avogadro constant). In one molecule of sulfur, S8, there are 8 sulfur atoms. Thus, number of atooms in 7.20 moles of sulfur = 8 x 7.20 x 6.02 x 1023 = 3.47 x 1025 Note: Sulfur does not usually exist in a monatomic form but instead forms cyclic octatomic molecules with molecular formula S8.
How many atoms are in .23 g Pb?
The number of atoms of lead is 6,68.10e23.
What is the molarity of a 5ml solution containing 0.7 micrograms of selenium?
The answer is1.77 * 10-6 M.Solution:.7 ug * (1 g \ 106 ug) This converts our value from micrograms (ug) to grams (g).* (1 mole Selenium \ 78.96 g Selenium) This gives out our # of moles Selenium by using Selenium's molar mass (78.96 g/mol).= 8.87 * 10-9 moles SeleniumDivided by the volume in liters (.005 L)= 1.77 * 10-6 moles Selenium \ 1 L (M)Check:.005 L * (1.77 * 10-6 moles Selenium\ 1 L)= .00000177 moles Selenium* (78.96 g Selenium \ 1 mole Selenium)* (106 ug \ 1 g)~= .7 ug.- Mike
How many atoms are in 49.1740 g of zirconium?
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
How many atoms are in 149 g of calcium?
149 g of calcium contain 22,39.10e23 atoms.
How many moles are in 12.2 grams of calcium?
12.2 g Ca/ 40.08 g/mol = .304 mol
How many atoms are in 38.260 g of chlorine?
6,687.1023 chlorine atoms
How many atoms are there in 63.5 g of carbon monoxide?
27,30.10e23 atoms
How many atoms are in g Pb?
The number of atoms of lead is 6,68.10e23.
How many atoms of sulfur (S) are in 5 g of sulfur?
5 g of sulfur contain 0,94.10e23 atoms.
