How many atoms are there in 61.7 g of selenium?

Answer 1

1 mol of sulfur contains 6.02 x 1023 molecules (avogadro constant).

In one molecule of sulfur, S8, there are 8 sulfur atoms.

Thus, number of atooms in 7.20 moles of sulfur

= 8 x 7.20 x 6.02 x 1023

= 3.47 x 1025

Note: Sulfur does not usually exist in a monatomic form but instead forms cyclic octatomic molecules with molecular formula S8.

Answer 2

For this problem, the Atomic Mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.

7.51 moles Se × (6.02 × 1023 atoms) = 4.52 × 1024 atoms

Answer 3

To find the number of atoms in 61.7 g of selenium, you need to convert grams to moles using the molar mass of selenium (78.971 g/mol), then use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of selenium to atoms. This calculation would give you the number of selenium atoms in 61.7 g.

Answer 4

78.96 g of Se has 6.023 x 1023 atoms

So, 28.1 g will have 2.14 x 1023 atoms

Answer 5

78.96 g of selenium will have 6.023 x 1023 atoms.

So, 61.7 g of selenium will have 4.71 x 1023 atoms.