5 g of sulfur contain 0,94.10e23 atoms.
64 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S) = 1.2 X 1024 atoms of sulfur ====================
78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
156,86.1020 atoms of uranium in 6,2 g uranium
The number of atoms is 28,099.10e23.
5 g of sulfur contain 0,94.10e23 atoms.
8 g sulfur have 1,5027176187149.1023 atoms.
16 g O x 1 mol/16 g = 1 mole and 1 mole = 6.02x10^23 atoms of O8g S x 1 mol/32 g = 0..25 moles S and then 0..25 moles x 6.02x10^23 atoms/mole = 1.5x10^23 atoms of S, or rounding to 1 significant figure, you have 2x10^23 atoms of S
1.00x10^-10 g Au x 1 mole Au/197 g x 6.02x10^23 atoms/mole = 3.06x10^11 atoms
The number of atoms of lead is 6,68.10e23.
32 g S * (1 mole S/32 g S) * (6.022*1023 atoms/1 mole S) = 6.022*1023 atomsThere are 6.022*1023 atoms in 32 grams of sulfur.
1.20x10^25 atoms S x 1 mole S/6.02x10^23 atoms x 32 g/mole S = 638 g
4Cr(s)+3O2(g)→2Cr2O3(g)
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
2(6.02*10 23) atoms
149 g of calcium contain 22,39.10e23 atoms.
64 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S) = 1.2 X 1024 atoms of sulfur ====================