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50% of 64 g compound XX = 32, so 32 g S = 1.0 mole S

50% of 64 g compound XX = 32, so 32 g O2 = 1.0 mole O2 or =2.0 mole O atoms

Thus it is SO2

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Q: What is the empirical formula of a compound whose composition by mass is 50 percent sulfur and 50 percent oxygen?
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