50% of 64 g compound XX = 32, so 32 g S = 1.0 mole S
50% of 64 g compound XX = 32, so 32 g O2 = 1.0 mole O2 or =2.0 mole O atoms
Thus it is SO2
If it tells you to find the empirical formula when percent composition is given or if the mass of each element is given in a specific compound.
Fe2S3, I think...
CaBr2 :)
Yes, if you have some additional information, such as the molecular weight. For instance, the molecules C2H4 and C4H8 have exactly the same percent composition, but they are very different molecules. So you need some other information to tell them apart than the percent composition.Answer ExpandedThis is kind of a trick question. By knowing the percent composition, you would easily be able to determine its empirical formula, but molecular formula is a bit different. The molecular formula is the actual number of atoms in a molecule, so in order to find the specific molecular formula of a substance, you would also need to know how many grams there is of that substance.(This explains the difference between C2H4 and C4H8)
The formula of the compound and the Atomic Mass of its elements.
Percent composition can be used to calculate the percentage of an element/compound in a mixture. From the percent composition, you can also find the empirical formula. And from the empirical formula you can find the actual molecular weight.
If it tells you to find the empirical formula when percent composition is given or if the mass of each element is given in a specific compound.
One atom of carbon, two of oxygen.
Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.
Chi a+
P2o5
Cr3Si2 is the empirical formula for a compound containing chromium and silicon an has 73.52 mass percent chromium.
CHI3
C3 h3o
p2o5
S2o3
KCl