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What are the parents if 75 of the offspring have a Dominant gene?
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There is a 50 percent chance the genotype of the offspring will contain a dominant geneCould this count as a correct way to explain the outcome of a punnet square?
No. The punnet square should yield 75% dominant. If the sides of the square are A and a versus A and a, capital A meaning the dominant gene, which expresses over the recessive gene "a" whenever it is present, then the possible outcomes in the square are: AA, Aa. aA, and aa. Three out of four, or 75%, are dominant.
What will have only two possible phenotypes?
Any cross of parents for a single trait where the dominant allele completely masks any expression of the recessive allele as follows:Parents are both heterozygous for the trait. For example Aa X Aa produces 75% of offspring with the dominant phenotype and 25% with the recessive phenotype.One parent is heterozygous for the trait and the other parent is homozygous recessive. For example: Aa X aa produces 50% offspring with the dominant phenotype and 50% offspring with the recessive phenotype.If the trait is co-dominant/non-dominant a heterozygote would have the median characteristic and a homozygote could be either of two phenotypes. If T is tall and t is short the Tt offspring would bemedium in this example. The way to produce offspring with only two phenotypes would be to cross a heterozygous parent with a homozygous parent. For Example:Tt X tt cross would produce 50% tt (short) offspring and 50% Tt (medium) offspring. A TT X Tt cross would produce 50% TT (tall) offspring and 50% Tt (medium) offspring.
Is being hairy a dominant or recessive gene?
It's depending on how your family is. If your family is 75% hairy and the 25% isn't then it's dominant your family is 25% hairy and 75% isn't then it's recessive. If it's 50/50 then it can go either way.
How many offspring are likely to have recessive traits if the parents are hybrids?
50%. There are four possible outcomes of the cross:dominant trait from "dad", dominant trait from "mom"recessive trait from "dad", dominant trait from "mom"dominant trait from "dad", recessive trait from "mom"recessive trait from "dad", recessive trait from "mom"Therefore, to get hybrid offspring (one dominant, one recessive), you have a 2 out of 4 chance.
In certain rats black fur is dominant over white fur If two rats both heterozygous for fur color are mated their offspring would be expected to have?
There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur
What percent of the offspring will most likely have brown fur?
If brown fur is a dominant trait in the offspring's parents, then approximately 75% of the offspring will most likely have brown fur. This is because there is a 75% chance that each offspring will inherit at least one dominant brown fur gene from the parents.
If both a mother and a father carry a dominant gene for dark eyes and a recessive gene for light eyes (Bb) what is the likelihood that their offspring will have dark eyes?
75%. If both parents are heterozygous, then using a punnet square, one can see that the dominant gene will show up in 3 out of 4 offspring.
There is a 50 percent chance the genotype of the offspring will contain a dominant geneCould this count as a correct way to explain the outcome of a punnet square?
No. The punnet square should yield 75% dominant. If the sides of the square are A and a versus A and a, capital A meaning the dominant gene, which expresses over the recessive gene "a" whenever it is present, then the possible outcomes in the square are: AA, Aa. aA, and aa. Three out of four, or 75%, are dominant.
Which is the dominant gene father has dark brown eyes mother has blue eyes?
Sure you don't mean heterozygous dominant? If you don't there would be no blue eyed offspring. Let's assume you meant heterozygous dominant.B = brownbl = blueBbl X Bbl1/4 of the offspring would have blue eyes, 25%.
What is probability that wto heterozygous parents would have an offspring that produced round seeds?
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
Percentage of types of offspring had the same phenotype as the parents?
75%
What perentage of the possible types of the offspring had the same genotype as the parents?
75%
What percentage of the possible types of offspring had the same phenotype as the parents?
Hey there. To answer this accurately, i would need to know the genotypes of both parents. I'll show you a trick that works them out in a flash. A phenotype is the result of a genotype, which is the result of 2 alleles. Say if both parents were HOMOZYGOUS for brown hair, with their genotype would be BB, BB. Use a trick called a punnet square to answer this; _|B |B | B|BB|BB| <-- not the best punnet square, but the top row shows the first parents B|BB|BB| genotype (BB) and the side shows the second's. (BB) The cross of this shows all the children will have brown hair, as inherited from each parent. If the Mother had HOMOZYGOUS brown hair (BB), and the father had HETEROZYGOUS brown hair (Bb) the results would be 100% Brown hair too, because the brown hair gene (B) is dominant over the non brown hair gene (b). Below; _|B |B | B|BB|BB| <--- this shows the cross gives a 50% chance to be Homozygous for brown b|Bb|Bb| hair but 50% heterozygous for brown hair, but carrying a non- brown hair gene. If we cross 2 heterozygous parents, the results are shown: _|B |b | B|BB|Bb| b|bB|bb| <----- This shows the child has a 75% chance of having brown hair (either (BB or bB, Bb) and 25% of being non-brown (bb)). This can be used in any gene cross, but you must keep in mind that one gene will be dominant and one will be recessive. I used the brown hair gene as an example here, as I don't know whether it may be dominant or recessive to other hair colours. Also, if you were after a global statistic, I wouldn't know. I hope this helps you. Fletch
What will have only two possible phenotypes?
Any cross of parents for a single trait where the dominant allele completely masks any expression of the recessive allele as follows:Parents are both heterozygous for the trait. For example Aa X Aa produces 75% of offspring with the dominant phenotype and 25% with the recessive phenotype.One parent is heterozygous for the trait and the other parent is homozygous recessive. For example: Aa X aa produces 50% offspring with the dominant phenotype and 50% offspring with the recessive phenotype.If the trait is co-dominant/non-dominant a heterozygote would have the median characteristic and a homozygote could be either of two phenotypes. If T is tall and t is short the Tt offspring would bemedium in this example. The way to produce offspring with only two phenotypes would be to cross a heterozygous parent with a homozygous parent. For Example:Tt X tt cross would produce 50% tt (short) offspring and 50% Tt (medium) offspring. A TT X Tt cross would produce 50% TT (tall) offspring and 50% Tt (medium) offspring.
If both parents are heterozygous for polydactyly what percentage of offspring will exhibit polydactyly?
75%
How do you prove gene dominance?
When two heterozygous organisms are mated, approximately 75% of these organisms should display the trait if it is dominant. 25% would display the recessive gene. If these numbers are very far off, chances are the gene you were testing was not a dominant trait.
What Blood type will a baby be from o positive parents?
well since O blood type is dominant the offspring will most likely have O+ if both parent genetic over cross is Bb (one of the parents parent has o+ blood while the other has A or B. there is a 75% chace the offspring will have O+ if both parents have genetic cross of BB (both of their parent has O blood) there is a 100% change the offspring will have O if one parent has genetic overcross BB and the other Bb it will still be 100% since BB is dominant. google punnet square
