To improve the power factor
Inductor impedance is given by jwL, where w=2*pi*frequency. Therefore as the frequency increases the impedance of the inductor increases, causing a larger current flow and a larger power dissipation across the inductor
in case of inductor or capacitor power factor is always zero.as power factor is cosine of phase angle between voltage and current. in case of inductor and capacitor phase angle between voltage and current is 90 so it become zero so if given power factor is zero then it can be inductor or capacitor.
Yes, it possible to heat a coil using dc power supply. An inductor resists a change in current, proportional to voltage and inversely proportional to inductance. The equation of an inductor is di/dt = v/L An ideal inductor, if connected to an ideal DC supply, with ideal conductors, would ramp up current in a linear fashion without limit, eventually reaching infinity amperes after infinite time. Since no inductor is ideal, nor is any DC supply, nor is any conductor, the current would reach a maximum based on the capacity of the DC supply and the DC resistance of the inductor and conductors. Since the DC resistance of the inductor is also not zero, this means, by Ohm's law, that the inductor must dissipate some power. That will cause the inductor to heat up.
Induction motor comprised inductor as the most part in it and an inductor has the characteristic to oppose the change of current, i.e., it has lagging power factor as current lags behind the voltage. Hence, an induction motor works on lagging power factor.
In an ideal inductor, no, there is no voltage induced across an inductor unless the current in the inductor is changing. However, since there are no ideal inductors nor power supplies, eventually an inductor will draw a constant current, i.e. the limit of the power supply; and, since no inductor has zero ohms at equilibrium, that current will translate to voltage.
An inductor is a device which stores energy as a magnetic energy.... Ideal inductor have no resistance.....so there is no power loss.... power loss = (I*I)*R
To improve the power factor
Inductor impedance is given by jwL, where w=2*pi*frequency. Therefore as the frequency increases the impedance of the inductor increases, causing a larger current flow and a larger power dissipation across the inductor
in case of inductor or capacitor power factor is always zero.as power factor is cosine of phase angle between voltage and current. in case of inductor and capacitor phase angle between voltage and current is 90 so it become zero so if given power factor is zero then it can be inductor or capacitor.
When a resistor and an inductor are both connected to an AC supply, the current in the resistor is in phase with the voltage, while the current in the inductor is a quarter-cycle (90 degrees) behind. Supposing they both draw 1 amp on a 12-volt AC supply. The resistor will dissipate 12 watts, while the inductor will dissipate no power. Any power that enters the inductor comes back to the generator in a later part of the cycle. But the current drawn from the supply is 1.414 amps, so this would be a load with a power factor of 0.707.
If it's a pure inductor, no power consumption. However it must be wound using unobtanium wire which has zero resistance, and the core must be vacuum. Air is nearly lossless.
Yes, it possible to heat a coil using dc power supply. An inductor resists a change in current, proportional to voltage and inversely proportional to inductance. The equation of an inductor is di/dt = v/L An ideal inductor, if connected to an ideal DC supply, with ideal conductors, would ramp up current in a linear fashion without limit, eventually reaching infinity amperes after infinite time. Since no inductor is ideal, nor is any DC supply, nor is any conductor, the current would reach a maximum based on the capacity of the DC supply and the DC resistance of the inductor and conductors. Since the DC resistance of the inductor is also not zero, this means, by Ohm's law, that the inductor must dissipate some power. That will cause the inductor to heat up.
The resistor is the only component to develop true power in an ac circuit. The inductor and capacitors absorb energy on one half cycle and return it to the supply on the next. The resistive part of the inductor (wire coil if low frequency type) will develop true power due to its value of resistance ie it will get warm.
Induction motor comprised inductor as the most part in it and an inductor has the characteristic to oppose the change of current, i.e., it has lagging power factor as current lags behind the voltage. Hence, an induction motor works on lagging power factor.
They are called I squared R losses. That is the formula for calculating power (P) in watts. P=I^2*R. I equals current in amps. R equals resistance in ohms. Also if the voltage (E) is known the formula is P=E^2/R. The current of electrons meets the resistance of the coil wire. That results in heat in inductor and transformer coils.
what is an inductor used for