Na+ and Cl-
Na+ and Cl- (APEX) I Wanna Give A Shout To My Momma And The squad Cant Forget Yall Day One Ni**as Oh Yea Rip LaCapone Free Rondo And Cdai They didnt Do It.Oh Yea I Hate MaverickHigh Miamidade
No, they are not spectator ions; H+ is a very strong acid and OH- is a very strong base. Na, Br (groups 1,2, and 7) are the spectator ions.
Na+ and Cl- are spectator ions.
Na and Cl
H+ and I- are the spectator ions.
Mg(s) + H2SO4(aq) ==> MgSO4(aq) + H2(g) ... molecular equationMg(s) + 2H+(aq) + SO4^2-(aq) ==> Mg^2+(aq) + SO4^2-(aq) + H2(g) ... ionic equationMg(s) + 2H^+(aq) ==> Mg^2+(aq) + H2(g) ... net ionic equationSpectator is SO4^2- (sulfate ion).
If the acid is a strong acid, it'll break into ions. If the acid is a weak acid, it won't break up. For instance H2SO4 is a strong acid. In water, It'll break it into 2H+ and SO4 2- An acid will dissociate it's H+ and whatever anion it was connected to. (ONLY IF IT IS A STRONG ACID!)
2H
2h means two handed
H+ and I- are the spectator ions.
Mg(s) + H2SO4(aq) ==> MgSO4(aq) + H2(g) ... molecular equationMg(s) + 2H+(aq) + SO4^2-(aq) ==> Mg^2+(aq) + SO4^2-(aq) + H2(g) ... ionic equationMg(s) + 2H^+(aq) ==> Mg^2+(aq) + H2(g) ... net ionic equationSpectator is SO4^2- (sulfate ion).
pure sulphuric acid was dissolved in water
2h + 2h + 2h = 6h
The two relevant half-equations are: [1] SO2 + 2H2O --> (SO4)2- + 4H+ + 2e [2] (Cr2O7)2- + 14H+ + 6e --> 2Cr3+ + 7H2O Multiply [1] by 3; add together; cancel down H+ and H2O. Giving: 3SO2 + (Cr2O7)2- + 2H+ --> 3(SO4)2- + 2Cr3+ + H2O (The potassium ions are spectator ions) Edit: Can the answerer please give the complete equation? The ionic one is pretty "obvious"; I would prefer the full one. Thanks
H2SO4 -----> 2H+ + SO4 -
2H + + SO4 2- <-> H2SO4 Sulfuric acid is the conjugate acid here.
An ionic equation can be solved by: 1)Writing and balancing the given equation (if necessary) eg: 2Na(s)+2HCl(aq) --> 2NaCl(aq)+H2(g) 2) Split the ions (only ions that are aqueous are split) eg: 2Na(s)+2H(aq)+2Cl(aq) -->2Na(aq)+2Cl(aq)+H2(g) 3) Cancel the spectator ions(spectator ions are ions which remain in their original state after the chemical reaction) eg: 2Na(s)+2H+2Cl(aq) --> 2Na(aq)+2Cl(aq)+H2(g) 4)Write the balanced ionic equation: eg:2Na(s)+2H(aq) -->2Na(aq)+H2(g)
Good question. Someone else will probably have a better answer than me but this is what I learnt at school. The water molecules breakdown the bonds between the hydrogen Ions (2H^[+1]) from what is left over (SO4^[-2]). From my understanding water is just a catalyst in this reaction. Water H2SO4 --------> 2H^[+1] + SO4^[-2] However again someone probably has a better explanation than me
Ca2+(aq) + SO42-(aq)- --> CaSO4(s) is the net ionic equation.
- 3h - 2h + 6h + 9 = h + 9
All acids have positive charge. Both mineral and carboxylic acids ionise to some degree in solution producig hydrogen ions H^(+). , Notice they are plus/positive. It is these ions that are the avid component on a substance. E.g. Mineral acid H2SO4 = 2H^(+) + SO4^(2-) e.g. Carboxylic acid CH3COOH = CH3COO^(-) + H^(+) The pH scale indicates the number of H^(+) ions in a solution. The lower the number , the more H^(+) ions.