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The two relevant half-equations are:

[1] SO2 + 2H2O --> (SO4)2- + 4H+ + 2e

[2] (Cr2O7)2- + 14H+ + 6e --> 2Cr3+ + 7H2O

Multiply [1] by 3; add together; cancel down H+ and H2O. Giving:

3SO2 + (Cr2O7)2- + 2H+ --> 3(SO4)2- + 2Cr3+ + H2O

(The potassium ions are spectator ions)

Edit: Can the answerer please give the complete equation? The ionic one is pretty "obvious"; I would prefer the full one. Thanks

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14y ago

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