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Q: What are the steps in a stoichiometry problem that starts with grams of a reactant?
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How do you solve stoichiometry?

You don't solve stoichiometry. The questions and answers that arise in stoichiometry are merely manipulations of permanent relationships between things (e.g. there are approximately 70.9 grams in one mole of chlorine gas). The conversions needed to report an answer of a stoichiometric problem are the part that take work to overcome mentally. One has to evaluate the units that a value starts with and the units the final answer requires and think about what conversions are needed in between.


If there are 4 grams of reactant how many grams of product are produced by the chemical reaction?

4


What are the major types of stoichiometry problems?

Conversions with units, especially getting atoms to moles to grams etc


How is stoichiometry used to calculate energy when a mass of liquid freezes?

Grams liquid × mol/g × Hfusion


How many grams carbon dioxide is made when 42 grams of propane is burned with 115 grams of oxygen how many grams of water is made?

First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g

Related questions

How do you solve stoichiometry?

You don't solve stoichiometry. The questions and answers that arise in stoichiometry are merely manipulations of permanent relationships between things (e.g. there are approximately 70.9 grams in one mole of chlorine gas). The conversions needed to report an answer of a stoichiometric problem are the part that take work to overcome mentally. One has to evaluate the units that a value starts with and the units the final answer requires and think about what conversions are needed in between.


In a chemical reaction 300 grams of reactant A are combined with 100 grams of reactant B . both A and B reactant to completion. how much will the product weigh?

200


Why is stoichiometry important to chemistry?

Stoichiometry is important to chemistry because it is how you find important things in chemistry like particles, grams, moles and liters.


What is the reactant of 10.0 grams of total mass What is the chemical reaction?

It is possible to have ten grams of anything. Specifying the total weight tells you nothing about which reactant you have or what reaction it will undergo.


87.2 grams of glucose burned in 87.2 grams oxygen what is limiting reactant?

Glucose


If there are 4 grams of reactant how many grams of product are produced by the chemical reaction?

4


Stoichiometry grams of N2 are needed to produce 20 grams NH3 N2 plus H2 NH3?

16,45 g nitrogen are needed.


What are the major types of stoichiometry problems?

Conversions with units, especially getting atoms to moles to grams etc


How is stoichiometry used to calculate energy when a mass of liquid freezes?

Grams liquid × mol/g × Hfusion


How is Stoichiometry use to calculate energy absorbed when a mass of liquid boils?

Grams liquid × mol/g × Hvap


How many grams carbon dioxide is made when 42 grams of propane is burned with 115 grams of oxygen how many grams of water is made?

First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g


How many moles in 29.22g of sodium chloride?

In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl