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You don't solve stoichiometry. The questions and answers that arise in stoichiometry are merely manipulations of permanent relationships between things (e.g. there are approximately 70.9 grams in one mole of chlorine gas). The conversions needed to report an answer of a stoichiometric problem are the part that take work to overcome mentally. One has to evaluate the units that a value starts with and the units the final answer requires and think about what conversions are needed in between.
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Conversions with units, especially getting atoms to moles to grams etc
Grams liquid × mol/g × Hfusion
First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g
You don't solve stoichiometry. The questions and answers that arise in stoichiometry are merely manipulations of permanent relationships between things (e.g. there are approximately 70.9 grams in one mole of chlorine gas). The conversions needed to report an answer of a stoichiometric problem are the part that take work to overcome mentally. One has to evaluate the units that a value starts with and the units the final answer requires and think about what conversions are needed in between.
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Stoichiometry is important to chemistry because it is how you find important things in chemistry like particles, grams, moles and liters.
It is possible to have ten grams of anything. Specifying the total weight tells you nothing about which reactant you have or what reaction it will undergo.
Glucose
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16,45 g nitrogen are needed.
Conversions with units, especially getting atoms to moles to grams etc
Grams liquid × mol/g × Hfusion
Grams liquid × mol/g × Hvap
First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl