131.108.16.65
To divide the network 192.168.1.0/24 into 6 subnets, we need to determine the subnet mask that accommodates at least 6 subnets. Using a /26 subnet mask (which allows for 4 subnets), we can go to /25 (which allows for 2 subnets) or /27 (which allows for 8 subnets). With a /27 subnet mask (255.255.255.224), we can create 8 subnets, each with 30 usable IP addresses. The resulting subnets would be: 192.168.1.0/27, 192.168.1.32/27, 192.168.1.64/27, 192.168.1.96/27, 192.168.1.128/27, and 192.168.1.160/27.
2 given subnets
Yes, the IP subnet 88.33.0.0 with a mask of 255.255.128.0 overlaps with the subnet 88.33.89.0 with the same mask. The subnet mask 255.255.128.0 indicates that the first 17 bits are the network part, meaning subnets can range from 88.33.0.0 to 88.33.127.255. Since 88.33.89.0 falls within this range, the two subnets indeed overlap.
There has to be some way of identifying how much of an address is the network portion and how much is client portion. The subnet mask identifies this. It may also indicate the presence of a series of subnets within a network. This is a required definition for operating within a LAN.
14 (+2 for network & host).
To calculate the number of usable subnets for the IP address 192.168.1.192, you first need to determine the subnet mask. Assuming a default Class C subnet mask of 255.255.255.0 (or /24), the address can be subnetted further. For example, if you use a /26 subnet mask (255.255.255.192), you can create 4 subnets (2^(26-24) = 4). Each of these subnets will have 62 usable IP addresses (64 total addresses minus 2 for the network and broadcast addresses).
To create 254 subnets in a Class B network, you need to borrow bits from the host portion of the address. Class B has a default subnet mask of 255.255.0.0 (or /16). To achieve 254 subnets, you need to use 8 bits for subnetting (2^8 = 256, minus 2 for network and broadcast addresses). This results in a new subnet mask of 255.255.255.0 (or /24), allowing for 254 usable subnets.
To create 8 subnets for the IP address 192.168.1.0, you need to use subnetting. Since 8 subnets require 3 additional bits (as 2^3 = 8), you can take 3 bits from the host part of the default subnet mask (255.255.255.0 or /24). This will change the subnet mask to 255.255.255.224 (/27), allowing for 8 subnets, each with 30 usable host addresses (2^5 - 2 = 30). The resulting subnets will range from 192.168.1.0 to 192.168.1.224.
The default subnet mask has a standard size. The custom subnet mask allows you to make subnets that are smaller or larger than the default.
255.255.255.0
To determine the number of subnets created for the host IP 195.70.16.93, you need to know the subnet mask. Without this information, it's impossible to provide a specific number of subnets. Generally, subnetting involves dividing a larger network into smaller ones by borrowing bits from the host portion of the address, which can vary based on the chosen subnet mask. If you provide the subnet mask or CIDR notation, I can give a more precise answer.
255.255.252.0