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I think , the basicity of sulphuric acid is 1.
To prepare 0.25N sulphuric acid from 2N sulphuric acid, you can dilute the 2N solution by adding 7 parts of water to 1 part of the 2N solution. This will result in a final 0.25N sulphuric acid solution.
1.Sulphuric acid (H2SO4) 2. Hydrochloric acid (HCl) 3. Nitric acid(HNO3) 4. Boric acid(H3BO3) 5. Hydrofluoric acid(HF) 6. Hydrobromic acid(HBr) 7.Chromic acid (H2CrO4)
98.078 g mol-1
The solutions of sulphuric acid and Nitric acids also have pH 1 or 2.
Sulphuric Acid is colourless. When universal indicator (UI) is added, sulphuric acid remains colourless. The universal indicator turns 'RED'. Howver, because the UI is in solution with the sulphuric acid, the solution appears to be red.
9,8 g concentrated sulphuric acid to 1 L of water (attention to mixing !)
1 mole sulfuric acid for 1 mole calcium chloride
H2SO4 = Sulphuric Acid This formula tells us that , in the molecule, there are;- 2 x hydrogen atoms 1 x sulphur atom 4 x oxygen atoms. Do NOT confuse with SULPHUROUS ACID , which as the formula H2SO3. The different is oner less oxygen atom.
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For preparation of 4N solution of sulphuric acid Dissolve 196 gm H2SO4 in 1000 ml DM water. Calculation N E V Weight = ------------ 1000 Where N= Normality E= Equivalent weight V= Volume
You wrote the wrong question. It should be: What is the balanced equation of ammonium sulphate from ammonium and dilute sulphuric acid? Well the answer will be (NH4)+1(S04)-2 which equals to (NH4)2 (SO4)