You can decrease the pressure. As pressure decreases, volume increases.
and vice versa
The formula to calculate the work done by a gas in a thermodynamic process is: Work Pressure x Change in Volume
When a gas expands isobarically (at constant pressure), the product of the pressure and the change in volume is equal to the work done by the gas during the expansion. Mathematically, this can be expressed as ( W = P \Delta V ), where ( W ) is the work done, ( P ) is the constant pressure, and ( \Delta V ) is the change in volume. This work is positive when the gas expands, indicating that energy is transferred from the gas to its surroundings.
In the context of thermodynamics, work done on a gas can be calculated using the formula W = PΔV, where P is pressure and ΔV is the change in volume. Since work done is measured in joules, pressure multiplied by volume change gives the work done in joules.
The formula for calculating the work done by an ideal gas in a thermodynamic process is: Work -PV where: Work is the work done by the gas, P is the pressure of the gas, and V is the change in volume of the gas.
If the space in which the gas is inside doesn't change, the volume of gas doesn't change
does gas take the shape of it's container and can change volume
The volume decreases
The matter that can change shape and volume is gas.
When the volume of a gas is doubled at constant atmospheric pressure, the work done on or by the gas can be calculated using the formula ( W = P \Delta V ), where ( P ) is the pressure and ( \Delta V ) is the change in volume. If the initial volume is ( V ) and the final volume is ( 2V ), then ( \Delta V = 2V - V = V ). Thus, the work done is ( W = P \times V ), where ( P ) is atmospheric pressure.
Change the pressure and/or the temperature of the gas.
The maximum amount of work that a gas can do during a constant-volume process is zero, because work done by a gas is given by the formula W = PΔV and volume change (ΔV) is zero in a constant-volume process.
The product of pressure times volume is equal to the work done on a gas. This relationship is described by the ideal gas law equation, which states that pressure multiplied by volume equals the number of moles of gas, the gas constant, and the temperature of the gas.