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When the volume of a gas is doubled at constant atmospheric pressure, the work done on or by the gas can be calculated using the formula ( W = P \Delta V ), where ( P ) is the pressure and ( \Delta V ) is the change in volume. If the initial volume is ( V ) and the final volume is ( 2V ), then ( \Delta V = 2V - V = V ). Thus, the work done is ( W = P \times V ), where ( P ) is atmospheric pressure.
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When a gas expands isobarically the product of the pressure and change of volume is equal to which one of these statements?
When a gas expands isobarically (at constant pressure), the product of the pressure and the change in volume is equal to the work done by the gas during the expansion. Mathematically, this can be expressed as ( W = P \Delta V ), where ( W ) is the work done, ( P ) is the constant pressure, and ( \Delta V ) is the change in volume. This work is positive when the gas expands, indicating that energy is transferred from the gas to its surroundings.
Identify the law that is associated with this formula PV c?
The formula PV = C is done by the Gas Law to measure pressure and volume's relationship.
How is the pressure and absolute temperature of a gas at constant volume related?
It is change in internal energy. If the volume of the system remains unchanged (isochoric process)then the heat given to the system is entirely utilized to increase the internal energy of that system. It is to be noted that no pressure-voulme work is done in such processes.
A gas in a piston is compressed from a pressure P1123000 Nm2 and volume V11.25 m3 to a pressure P2445000 Nm2 and a volume V20.81 m3 There is no heat transferred to the environment The compress?
The work done on the gas during compression is given by the formula W = PΔV, where P is the average pressure and ΔV is the change in volume. So, the work done on the gas during compression is (1123000 + 2445000)/2 * (20.81 - 11.25) = 10600475 J. Since no heat is transferred to the environment and the process is adiabatic, the change in internal energy of the gas is equal to the work done on the gas, so ΔU = 10600475 J.
How can you increase the air pressure inside a bag containing a group of air molicules?
You can increase the air pressure inside the bag by reducing the volume of the bag or adding more air molecules to it. This can be done by squeezing the bag to decrease its volume or blowing air into the bag to increase the number of air molecules present inside.
When the pressure exerted on a confined gas at a constant temperature is doubled the volume of the gas is?
Pressure will be doubled as well, if done in the samevolume (so: not in a balloon I mean).(Gas law: p/T=constant )
What can be done to change the volume of gas?
You can decrease the pressure. As pressure decreases, volume increases. and vice versa
How is pressure volume equal to a joule?
In the context of thermodynamics, work done on a gas can be calculated using the formula W = PΔV, where P is pressure and ΔV is the change in volume. Since work done is measured in joules, pressure multiplied by volume change gives the work done in joules.
How does the relationship between pressure, volume, and work manifest in the context of thermodynamics?
In thermodynamics, the relationship between pressure, volume, and work is described by the equation: work pressure x change in volume. This means that when pressure increases or volume decreases, work is done on the system, and when pressure decreases or volume increases, work is done by the system. This relationship helps to understand how energy is transferred and transformed in thermodynamic processes.
What is the work done in an isothermal process?
In an isothermal process, the work done is the product of the pressure and the change in volume of the system. This is because the temperature remains constant throughout the process, so the work done is solely determined by the change in volume.
How can the pressure volume diagram be used to analyze the thermodynamic processes of a system?
The pressure-volume diagram can be used to analyze the thermodynamic processes of a system by showing how pressure and volume change during different stages of the process. This diagram helps in understanding the work done, heat transfer, and efficiency of the system.
What is the work done in an isobaric expansion?
The work done in an isobaric expansion is given by the formula: work = pressure x change in volume. This is because in an isobaric process, the pressure remains constant while the volume changes, resulting in work being done on or by the system.
What is a demonstration of pressure could be done best with what?
A demonstration of pressure could be done best with a balloon and a pump. By inflating the balloon using the pump, the increasing pressure inside the balloon can be observed by its expansion. This can help illustrate how pressure can cause a volume to change.
When a gas expands isobarically the product of the pressure and change of volume is equal to which one of these statements?
When a gas expands isobarically (at constant pressure), the product of the pressure and the change in volume is equal to the work done by the gas during the expansion. Mathematically, this can be expressed as ( W = P \Delta V ), where ( W ) is the work done, ( P ) is the constant pressure, and ( \Delta V ) is the change in volume. This work is positive when the gas expands, indicating that energy is transferred from the gas to its surroundings.
What is the product of pressure times volume?
The product of pressure times volume is equal to the work done on a gas. This relationship is described by the ideal gas law equation, which states that pressure multiplied by volume equals the number of moles of gas, the gas constant, and the temperature of the gas.
How much work is done by the gas during this expansion?
The work done by the gas during the expansion is equal to the area under the pressure-volume curve on a graph of the process.
What is the formula to calculate the work done by a gas in a thermodynamic process?
The formula to calculate the work done by a gas in a thermodynamic process is: Work Pressure x Change in Volume
