The object is moving at a constant speed.
Distance is equal to magnitude of displacement when the motion is in a straight line.
You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!
the displacement mean the shortest distance between two points. the shape of displacement where the objects move and its also help us to tell the shape of displacement with the use of graph.
No you cannot.A displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero even though it is far from stationary.
If the distance/time graph is a straight line that makes a constant angel with the time axis, then the body's speed is constant, and is equal to the slope of the straight line (tangent of the constant angel).
yo yo
the body is in accelerated motion.
Distance is equal to magnitude of displacement when the motion is in a straight line.
A displacement vs. time graph of a body moving with uniform (constant) velocity will always be a line of which the slope will be the value of velocity. This is true because velocity is the derivative (or slope at any time t) of the displacement graph, and if the slope is always constant, then the displacement will change at a constant rate.
That the body, whose motion is being plotted is not moving radially. It can be moving along a circle with the origin as the centre at any speed but that does not show up in a displacement-time graph.
You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!
You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!
uniformly accelerated motion
the displacement mean the shortest distance between two points. the shape of displacement where the objects move and its also help us to tell the shape of displacement with the use of graph.
No you cannot.A displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero even though it is far from stationary.
The motion of a body towards and from some fixed point. It can also be used to find the acceleration (or deceleration) in the same direction or the total distance from the fixed point in the direction of motion. But the graph gives no information at all on motion in any other direction. So, the horizontal displacement of a rocket going straight up would always be 0!
No.The displacement-time graph of a moving body can not be a straight line perpendicular to the time axis. A graph like that would indicate that the body moved with infinite speed, moved from one place to another in zero time, or occupied many different places at the same time. Considerable evidence has piled up which suggests that none of those things can happen.