2KClO3(s)+MnO2(s) → 2KCL(s)+3O2(g)
KClO3+3H2SO3=KCl+3H2SO4
kclo3
There is no such thing as KCIO3. That should be a lowercase L, not an I. (all two-letter element symbols use a lowercase for the second letter) That being said, KClO3 is Potassium Chlorate. K = Potassium Cl = Chlorine O = Oxygen 3 = number of Oxygen atoms in the molecule
Potassium chlorate (KClO3) has 3 oxygen atoms.
CAtalyst
KClO3
3 moles of oxygen are obtained from 2 moles of potassium chlorate.M of KClO3 is 122,55 g, M of O2 is 32, density of oxygen is 1,429 g/L.
A 1.80-gram mixture of potassium chlorate, kclo3, and potassium chloride, kcl, was heated until all of the kclo3 had decomposed the liberated oxygen, after drying, occupied 405 ml at 25C when the barometric pressure was 745 torr. This is the problem and the questions were... a. How many moles of O2 were produced? b. What percent of the mixture was KClO3? KCl? Please help!!
This reaction is:2 KClO3 = 3 O2 + 2 KCl
The formula for potassium chlorate is KClO3.
On heating potassium chlorate decomposes on potassium chloride and oxygen. 2KClO3------>2KCl+3O2 9.8g of KClO3 are heated. Calculate a. the mass of KCl formed. b. the mass and volume, at (s.t.p) of O2 formed.
KClO3+3H2SO3=KCl+3H2SO4
The name of the compound with the formula KClO3 is "potassium chlorate".
KClO3
Chlorine is soluable, potassium however I think not. KClO3 is an ionic compound though.
because kCLO3 already contain oxygen. so, it can't be determine which one oxygen came from.
No: KClO3 is the formula for potassium chlorate, but the formula for potassium chloride is simply KCl.