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A mixture of KCl and KNO3 is 44.20 percent potassium by mass the percentage of kcl in the mixture is?
To find the percentage of KCl in the mixture, we first need to determine the percentage of potassium coming from KCl. Since the mixture is 44.20% potassium by mass and KCl is 74.55% potassium by mass, we can set up a simple ratio to find the percentage of KCl in the mixture as (74.55% / 100%) * 44.20% = 32.97%. Therefore, the percentage of KCl in the mixture is approximately 32.97%.
How many moles are in 74 g of KCl?
To find the number of moles in 74 g of KCl, you first need to calculate the molar mass of KCl. The molar mass of KCl is approximately 74.55 g/mol. Then, divide the given mass by the molar mass to get the number of moles: 74 g / 74.55 g/mol ≈ 0.993 moles.
How many mols in 74g of KCl?
1 mole.
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
To calculate the grams of KCl needed, first determine the molar mass of KCl (74.55 g/mol). Then use the formula: grams = molarity x volume (L) x molar mass. Plugging in the values, you get: grams = 0.75 mol/L x 2.25 L x 74.55 g/mol = 126.60 grams of KCl.
How many grams of KCl to make 50 mL of 2.45 M KCl?
To calculate the grams of KCl needed, first calculate the moles of KCl required using the molarity formula. Then, convert moles to grams using the molar mass of KCl, which is approximately 74.55 g/mol.
If the mass with 0.1 grams of MNO2 is 53.300g and 20 g of KCl O3 is 73.300g and after burning it so only KCl remains is 65.467 g what is mass of potassium chloride?
The mass of KCl in the mixture can be calculated by subtracting the mass of the remaining components from the initial mass after burning. For the first mixture, after burning it, the mass of MnO2 and KClO3 will be removed, leaving only KCl. Therefore, subtract 65.467g (mass after burning) from 53.300g (initial mass) to find the mass of KCl, which is 12.133g.
Why is the mass of KCL recovered less the starting mass of KHCO3?
The mass of KCl recovered is less than the starting mass of KHCO3 because during the chemical reaction between KHCO3 and HCl to form KCl, CO2 gas is evolved. Some of the starting mass of KHCO3 is lost as gas during the reaction, leading to a lower mass of the end product (KCl) compared to the original mass of KHCO3.
A mixture of KCl and KNO3 is 44.20 percent potassium by mass the percentage of kcl in the mixture is?
To find the percentage of KCl in the mixture, we first need to determine the percentage of potassium coming from KCl. Since the mixture is 44.20% potassium by mass and KCl is 74.55% potassium by mass, we can set up a simple ratio to find the percentage of KCl in the mixture as (74.55% / 100%) * 44.20% = 32.97%. Therefore, the percentage of KCl in the mixture is approximately 32.97%.
What is the balanced equation for heating potassium chloride?
There is no reaction (decomposition) when KCl is heated, other than the melting of KCl, above its melting point.
How many moles are in 74 g of KCl?
To find the number of moles in 74 g of KCl, you first need to calculate the molar mass of KCl. The molar mass of KCl is approximately 74.55 g/mol. Then, divide the given mass by the molar mass to get the number of moles: 74 g / 74.55 g/mol ≈ 0.993 moles.
How many mols in 74g of KCl?
1 mole.
How many moles are in 550 grams of KCl?
To calculate the number of moles in 550 grams of KCl, first find the molar mass of KCl. Potassium (K) has a molar mass of 39.10 g/mol and chlorine (Cl) has a molar mass of 35.45 g/mol. Add these together to get the molar mass of KCl, which is 74.55 g/mol. Divide the given mass (550 grams) by the molar mass (74.55 g/mol) to find the number of moles. In this case, there are approximately 7.39 moles of KCl in 550 grams.
How many grams are in 3.75 moles of kcl?
To find the number of grams in 3.75 moles of KCl, you would first calculate the molar mass of KCl, which is approximately 74.55 g/mol. Then, you would multiply this molar mass by the number of moles (3.75 moles) to get the answer, which is 279.56 grams of KCl.
How many moles are in 12.57 grams of KC1?
To find the number of moles in 12.57 grams of KCl, you need to first calculate the molar mass of KCl which is approximately 74.55 g/mol. Then, divide the given mass (12.57g) by the molar mass to get the number of moles, which is approximately 0.1685 moles.
What mass of KCl is required to prepare 383.00 mL of 0.500 M solution?
I'll go straight to the equation, to prepare 0.5 M of KCl in 383 ml, simply calculate it this way, *Molar mass of KCl is 74.5513 g/mol *0.5 M is also known as 0.5 mol/Litre 74.5513 g/mol x 0.5 mol/litre x 0.383 Litre = 14.2766 g So, you need 14.2766 g of KCl to prepare 0.5 M in 383 ml solution.
Calculate the mass in grams of 2.60 mol of potassium chloride (KCl).?
You can calculate the molar mass of potassium chloride (KCl) by adding the atomic masses of potassium (K = 39.10 g/mol) and chlorine (Cl = 35.45 g/mol). The molar mass of KCl is 74.55 g/mol. To find the mass of 2.60 mol of KCl, multiply the molar mass by the number of moles: 2.60 mol * 74.55 g/mol = 193.53 grams.
How many grams of potassium chloride is contained in 750 ml of 1.25 M KCl solution?
we know that, molarity=(given mass/molar mass)*(1000/volume of solution in ml) all the dats are given,only we have to find out the given mass or the present mass of the KCl. 1.25=(given mass/74.5)*(1000/750) => given mass=(1.25*750*74.5)/1000 =69.84g.
