You can calculate the molar mass of potassium chloride (KCl) by adding the atomic masses of potassium (K = 39.10 g/mol) and chlorine (Cl = 35.45 g/mol). The molar mass of KCl is 74.55 g/mol. To find the mass of 2.60 mol of KCl, multiply the molar mass by the number of moles: 2.60 mol * 74.55 g/mol = 193.53 grams.
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
To prepare a 40% potassium chloride solution in 100g of water, you would need to calculate the mass of potassium chloride required. Since the solution is 40% potassium chloride, that means 40g of the total solution mass must be potassium chloride. Therefore, you would need to add 40g of potassium chloride to the 100g of water to prepare the solution.
To determine the number of moles in 0.98 grams of Potassium chloride, you need to divide the given mass by the molar mass of Potassium chloride. The molar mass of KCl is approximately 74.55 g/mol. So, 0.98 grams / 74.55 g/mol ≈ 0.013 moles of KCl.
To calculate the number of moles of potassium chloride in a 100.0g sample, you need to divide the mass of the sample by the molar mass of potassium chloride. The molar mass of potassium chloride is approximately 74.55 g/mol. Therefore, 100.0g ÷ 74.55 g/mol = approximately 1.34 moles of potassium chloride in the sample.
the solubility of potassium nitrate in 70 degreesCelsius water is about 134 g KNO3 per 100 g water
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
To prepare a 40% potassium chloride solution in 100g of water, you would need to calculate the mass of potassium chloride required. Since the solution is 40% potassium chloride, that means 40g of the total solution mass must be potassium chloride. Therefore, you would need to add 40g of potassium chloride to the 100g of water to prepare the solution.
To determine the number of moles in 0.98 grams of Potassium chloride, you need to divide the given mass by the molar mass of Potassium chloride. The molar mass of KCl is approximately 74.55 g/mol. So, 0.98 grams / 74.55 g/mol ≈ 0.013 moles of KCl.
To calculate the number of moles of potassium chloride in a 100.0g sample, you need to divide the mass of the sample by the molar mass of potassium chloride. The molar mass of potassium chloride is approximately 74.55 g/mol. Therefore, 100.0g ÷ 74.55 g/mol = approximately 1.34 moles of potassium chloride in the sample.
the solubility of potassium nitrate in 70 degreesCelsius water is about 134 g KNO3 per 100 g water
To calculate the mass of 2x10^12 atoms of potassium, you first need to find the molar mass of potassium (39.10 g/mol). Then, divide the number of atoms by Avogadro's number to get the moles of potassium. Finally, multiply the moles by the molar mass to find the mass in grams, which in this case would be 0.01566 grams.
To make a 3 Molar solution of potassium chloride in 250 milliliters: Calculate the mass of potassium chloride needed using its molar mass. Dissolve this mass of potassium chloride in a small amount of water, then add water to bring the total volume to 250 ml. Stir to ensure complete mixing and dissolve the potassium chloride completely.
The molar mass of potassium chloride is 74,5513.
To calculate the milliequivalents of chloride ions in 0.725 grams of chloride, you first need to determine the molar mass of chloride (Cl⁻) which is 35.45 g/mol. Next, calculate the number of moles in 0.725 grams by dividing the mass by the molar mass. Then, convert moles to milliequivalents by multiplying by 1000 (since 1 mole of ions = 1000 milliequivalents).
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
The decomposition of potassium chlorate produces oxygen gas and potassium chloride. The molar ratio of oxygen to potassium chlorate is 3:2. Therefore, to find the grams of oxygen produced, you would calculate (6.02g * 3 mol O2/2 mol KClO3) * molar mass of O2.
The molar mass of anhydrous aluminum chloride is 133,34 grams.