What is the mass, in grams, of 2 × 1012 atoms of potassium?
To calculate the number of potassium atoms, you first need to convert the mass of potassium to moles using the molar mass of potassium (39.10 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of potassium atoms present in the given mass.
To find the grams of potassium in K2CrO7, first determine its molar mass. Potassium (K) has a molar mass of 39.10 g/mol, and K2CrO7 has two potassium atoms, so (39.10 g/mol) * 2 = 78.20 g/mol. Then, divide the mass of K2CrO7 by its molar mass to get the grams of potassium: (27.8 g) / (294.19 g/mol) ≈ 9.45 g of potassium.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
Simple: the atomic weight expressed in grams. Example for dysprosium - 162,500 grams.
The molar mass for potassium iodide is 166,0028.
The mass is 2.86 grams but the weight will be 0.028 Newtons.
To calculate the number of potassium atoms, you first need to convert the mass of potassium to moles using the molar mass of potassium (39.10 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of potassium atoms present in the given mass.
The gram atomic mass of gold is 196.967 and that of potassium is 39.0983. Therefore, equal numbers of atoms of potassium are supplied by 39.0983/196.967 the mass of potassium compared with gold. 5 X 9.85 = 49.25. This contains the same number of gold atoms as 49.25(39.0983/196.967) or 9.78 grams of potassium contains of potassium atoms, to the justified number of significant digits (limited by the number "9.85", assuming that "5" is intended to be exact.)
To find the grams of potassium in K2CrO7, first determine its molar mass. Potassium (K) has a molar mass of 39.10 g/mol, and K2CrO7 has two potassium atoms, so (39.10 g/mol) * 2 = 78.20 g/mol. Then, divide the mass of K2CrO7 by its molar mass to get the grams of potassium: (27.8 g) / (294.19 g/mol) ≈ 9.45 g of potassium.
To find the number of potassium (K) atoms in 78.2 grams, first determine the molar mass of potassium, which is approximately 39.1 g/mol. Dividing 78.2 grams by the molar mass gives about 2.00 moles of potassium. Since one mole contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), multiplying 2.00 moles by (6.022 \times 10^{23}) results in approximately (1.20 \times 10^{24}) potassium atoms.
Potassium in grams:per mole: 39.10 gram/moleper atom: 39.10 (a.m.u./atom) * 1.6605.10-24(g/a.m.u.) = 64.93 *10-24 gramper Liter: 0.860 kg/L = 860 gram/L (as solid at STP)
Every atom of potassium has a mass of 39 amu. Each mole of potassium has a mass of 39 grams.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
Simple: the atomic weight expressed in grams. Example for dysprosium - 162,500 grams.
The molar mass for potassium iodide is 166,0028.
To find the number of moles in 5 grams of potassium sulfate (K2SO4), first calculate the molar mass of K2SO4 by adding the atomic masses of potassium (K), sulfur (S), and four oxygen (O) atoms. Then, divide the given mass (5 grams) by the molar mass of K2SO4 to get the number of moles.
1 mole K atoms = 39.0983g K (atomic weight in grams)1 mole K atoms = 6.022 x 1023 atoms K (Avogadro's number)Convert known atoms to moles.1.72 x 1023 atoms K x (1mol K/6.022 x 1023 atoms K) = 0.286mol KConvert moles to mass in grams.0.286mol K x (39.0983g K/1mol K) = 11.2g K