.01456 g (6.02 x 1023 atoms) / (39.1 g) = 2.24 x 1020 atoms
To calculate the mass of 2x10^12 atoms of potassium, you first need to find the molar mass of potassium (39.10 g/mol). Then, divide the number of atoms by Avogadro's number to get the moles of potassium. Finally, multiply the moles by the molar mass to find the mass in grams, which in this case would be 0.01566 grams.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
To find the grams of potassium in K2CrO7, first determine its molar mass. Potassium (K) has a molar mass of 39.10 g/mol, and K2CrO7 has two potassium atoms, so (39.10 g/mol) * 2 = 78.20 g/mol. Then, divide the mass of K2CrO7 by its molar mass to get the grams of potassium: (27.8 g) / (294.19 g/mol) ≈ 9.45 g of potassium.
30.115*10^23 molecules
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
To calculate the mass of 2x10^12 atoms of potassium, you first need to find the molar mass of potassium (39.10 g/mol). Then, divide the number of atoms by Avogadro's number to get the moles of potassium. Finally, multiply the moles by the molar mass to find the mass in grams, which in this case would be 0.01566 grams.
6
The mass is 2.86 grams but the weight will be 0.028 Newtons.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
The gram atomic mass of gold is 196.967 and that of potassium is 39.0983. Therefore, equal numbers of atoms of potassium are supplied by 39.0983/196.967 the mass of potassium compared with gold. 5 X 9.85 = 49.25. This contains the same number of gold atoms as 49.25(39.0983/196.967) or 9.78 grams of potassium contains of potassium atoms, to the justified number of significant digits (limited by the number "9.85", assuming that "5" is intended to be exact.)
To find the number of potassium (K) atoms in 78.2 grams, first determine the molar mass of potassium, which is approximately 39.1 g/mol. Dividing 78.2 grams by the molar mass gives about 2.00 moles of potassium. Since one mole contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), multiplying 2.00 moles by (6.022 \times 10^{23}) results in approximately (1.20 \times 10^{24}) potassium atoms.
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
To find the grams of potassium in K2CrO7, first determine its molar mass. Potassium (K) has a molar mass of 39.10 g/mol, and K2CrO7 has two potassium atoms, so (39.10 g/mol) * 2 = 78.20 g/mol. Then, divide the mass of K2CrO7 by its molar mass to get the grams of potassium: (27.8 g) / (294.19 g/mol) ≈ 9.45 g of potassium.
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
Potassium in grams:per mole: 39.10 gram/moleper atom: 39.10 (a.m.u./atom) * 1.6605.10-24(g/a.m.u.) = 64.93 *10-24 gramper Liter: 0.860 kg/L = 860 gram/L (as solid at STP)
30.115*10^23 molecules
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium