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In this case it really doesn't matter with which you start C or H, but mostly start with the simplest numbered: C. (Here the molecular coefficient is SET to a = 1 for C3H8, later it can be changed to a higer value when other coefficient are not a whole number)Never start with the oxygen, it is in two products and can't be solved first.aC3H8 + bO2 --> pCO2 + qH2OC: 3a = p , if SET a=1, then p=3H: 8a = 2q , if SET a=1, then q=4So far:1C3H8 + bO2 --> 3CO2 + 4H2O leaving b to be solved to a (whole) natural numberThen:O: 2b = 2p + q = 6 + 4 then b = 5Solved:C3H8 + 5O2 --> 3CO2 + 4H2O
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
Burning of propane:CH3H8 + 5 O2 = 3 CO2 + H2OBurning of butane:2 CH4H10 + 13 O2 = 8 CO2 + 10 H2O
The valence shell is the outter most shell that contains the most electrons. To find out how many valences there are you would mulitply the electrons. C3H8= (6)3 + (1)8=26 the outer valence shell will be 20.
5
5
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
Yes it is ..... Its Propane (C3H8)
C3h8+ 5o2---> 3co2+ 4h2o
this is tricky :|......this is as much as i can give you:3C+8H-------->?OI am unable to give you a good answer but i hope i gave you somethingim very sorry :[
Boiling point of C3H8 is -42 degree celsius.
In this case it really doesn't matter with which you start C or H, but mostly start with the simplest numbered: C. (Here the molecular coefficient is SET to a = 1 for C3H8, later it can be changed to a higer value when other coefficient are not a whole number)Never start with the oxygen, it is in two products and can't be solved first.aC3H8 + bO2 --> pCO2 + qH2OC: 3a = p , if SET a=1, then p=3H: 8a = 2q , if SET a=1, then q=4So far:1C3H8 + bO2 --> 3CO2 + 4H2O leaving b to be solved to a (whole) natural numberThen:O: 2b = 2p + q = 6 + 4 then b = 5Solved:C3H8 + 5O2 --> 3CO2 + 4H2O
C3H8 + 5O2 >> 3CO2 + 4H2O ( and, of course, energy )
The answer is: C3H8 + 5O2 3CO2 + 4H2O
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
C3H8 is the chemical formula for propane. Propane is a common fuel source for outdoor grills, and it is also a source of fuel for isolated areas that do not have connections to gas lines.