We know that the alkali metal sodium (Na) will form an ionic bond with the halogen bromine (Br) to create sodium bromide (NaBr). The equation looks like this:
Na + Br => NaBr
Sodium Bromide. Chemical formula: NaBr
Sodium Fluoride Sodium fluoride, but if you add oxygen, it becomes Sodium Fluorate.
They form Sodium Bromide
Bromine is an element and can't be "made" from any other element (except by a nuclear reaction). However, since the question asks for a sodium compound, one possibility is sodium bromide, which can be melted and electrolyzed to form bromine at the anode.
The compound formed between sodium and selenium is named "sodium selenide" and has the formula Na2Se.
No binary compound between beryllium and sodium.
The compound sodium bromide is formed by the formation of ionic bonds between sodium and bromide ions.
Sodium Fluoride Sodium fluoride, but if you add oxygen, it becomes Sodium Fluorate.
They form Sodium Bromide
Sodium Bromide - ionic compound - NaBr.
A group hydroxide doesn't exist.
Sodium (Na), and fluorine (F) combine to form sodium fluoride (NaF).
NaBr
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
Sodium bromide(NaBr) is formed
Sodium selenide is a compound formed between sodium and selenium.
Bromine is an element and can't be "made" from any other element (except by a nuclear reaction). However, since the question asks for a sodium compound, one possibility is sodium bromide, which can be melted and electrolyzed to form bromine at the anode.
The compound formed between sodium and selenium is named "sodium selenide" and has the formula Na2Se.