Yes it contains the lead (IV) ion.
The Answer To Your Question Is.... tin (IV) oxide
Tin(III) Phosphate
Tin exists in two compounds with oxygen. These compounds vary because of the different oxidation states of tin. The first compound is tin(II) oxide (Sn2+O2-). The second compound is tin(IV) oxide (Sn4+O22-).
Assuming that both elements are in their most common isotopes, Tin IV oxide has 86 neutrons (Tin 70, Oxygen 8 x2)
how many proton and electron are in the tin IV ion
The formula for the tin four ion is Sn+4
Tin(IV) = Sn4+Chloride = Cl-Formula = SnCl4
Sn4+
A Stannic ion is the ion of Tin(IV). Its formula is Sn4+ . Here tin is in its highest oxidation state of +4. The other ion is Stannous(Sn2+).
Yes it contains the lead (IV) ion.
Sn(CrO4)2 Tin 4 means that the tin is a cation with a +4 charge. Chromate is a polyatomic ion with the formula (CrO4)-2. Since the tin ion has a +4 charge in this case, and the chromate ion has a -2 charge, there is a 1:2 ratio of tin ions to chromate ions.
It is Tin(II) oxide or Stannous oxide
*Tin Sulfate* NO! This is WRONG!SnS2 is Tin(IV) Sulfide, not Tin SulfateThe (IV) means that Tin has a 4+ charge (can be Tin(II) with a 2+ charge or Tin(IV))Sulfur has a 2- charge, so it takes 2 Sulfur ions to balance out the chargesso you have 1 Tin Ion with a charge of 4+ and 2 Sulfur Ions with charges of 2+put them together and it makes SnS2Sulfate is a polyatomic ion with the formula SO4 with a 2- charge, so the formula for Tin Sulfate would be Sn(SO4)2
If you mean Sn2+ it is known as Tin(II) ion in the stock system or stannous ion in the old naming system.
The tin ion, Sn2+, and the nitrate ion, NO3-.
The formula for the compounds: Chromium (VI) Phosphate; Vanadium (IV) Carbonate; Tin (II) Nitrite?