ps1 = PlayStation 1 ps2=playstaion 2
P1/t1=p2/t2
Answer: Apex ↓Ptotal = P1 + P2 + P3 + ...
* 0.4A * (voltage of device V) = Power in watts P1 * P1/1000 = Power in kW P2 * P2 * (electric rate in dollars per kWhr) = Cost dollars/hr C * C * (days in this month) * 24 hr/day = Cost in dollars for this month
To solve for the original pressure of the helium gas, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. Using this law, we can set up the equation (P1)(V1) = (P2)(V2), where P1 is the original pressure, V1 is the original volume, P2 is the final pressure, and V2 is the final volume. Plugging in the values gives us (P1)(200 mL) = (300 mm Hg)(0.240 mL). Solving for P1 gives us P1 = (300 mm Hg)(0.240 mL) / 200 mL = 0.36 mm Hg. Therefore, the original pressure of the helium gas was 0.36 mm Hg.
You have for an Ideal Gas:PV = mRT/M( P2 ) ( V2 )/ (T2 ) ( m2 ) = ( P1 ) ( V1 ) / ( m1 ) ( T1 ) = R/M = ConstantV2 = ( V1 ) ( P1 /P2 ) ( T2/T1 ) ( m2 /m1 )You have :( P1 / P2 ) = 1.00( T2 / T1 ) = 1.00( m2 / m1 ) = 2.00V2 = ( V1 ) ( 1.000 ) ( 1.000 ( 2.000 ) = ( 2.000 ) ( V1 )
Let p1 and p2 be the two prime numbers. Because they are prime, their divisors are div(p1) = {1,p1} and div(p2) = {1,p2}. So GCD(p1,p2) = Greatest Common Divisor of p1 and p2 = p1 if p1 equals p2 1 if p1 is different from p2
No. Let p1 be a prime number. Let p2 be a multiple of p1 such that p2 = p1 * k. Then the factors of p2 are: 1, p1, k and p2. ==> p2 is not a prime number. Hence, a multiple of a prime number cannot be a prime number.
Assignment. Eg: void *p1, *p2; p2= p1;
If the old population is P1, the new population is P2, and the growth rate is G, G = (P2 - P1) ÷ P1 x 100%
(p1/v1) = (p2/v2)For Apex (P1 N1)= (P2N2 )
A pointer can point to address of another pointer. consider the exampleint x=456, *p1, **p2;p1 = &x;p2 = &p1;Copyright Einstein College of EngineeringDepartment of Civil EngineeringTOPprintf("%d", *p1); will display value of x 456.printf("%d", *p2); will also display value of x 456. This is because p2 point p1, and p1 points x.Therefore p2 reads the value of x through pointer p1. Since one pointer is points towards anotherpointer it is called chain pointer. Chain pointer must be declared with ** as in **p2
Price elasticity demand formula end point formula epd= [q2-q1/q1]/[p2-p1/p1] midpoint formula epd= [q2-q1/(q2+q1)/2] / [p2-p1/(p2+p1)/2]
The formula for computing elasticity of demand is: (Q1 - Q2) / (Q1 + Q2) ------------------------------ (P1 - P2) / (P1 + P2)
The general function is:1. y = a*x+bb is irrelevant and we can be removed2. y = a*xlets split x into ones and tens3. x = tens*10 + ones /e.g. 23 = 2*10 + 34. p1 = Multiplier of the onesp2 = Multiplier of the tens5. y = tens*10*p2 + ones*p1 /according to the question6. x*a = tens*10*p2 + ones*p1 /according to 2.7. (tens*10 + ones)*a = tens*10*p2 + ones*p1 /according to 3.8. tens*10*a + ones*a = tens*10*p2 + ones*p1 /regroup9. tens*10*a - tens*10*p2 + ones*a - ones*p1 = 0 /regroup10. tens*10*(a-p2) + ones*(a-p1) = 0 /regroup11. assuming "tens" and "ones" are not 0 then (a-p2) and (a-p1) must be 012. a-p2 = 0a-p1 = 013. a = p2a = p114. a = p1 = p2the answer is: when the Multipliers of ones and tens are equal then the product is called a.
ed=(q1-q2)/q1/(p1-p2)/p1
void PrintTwinPrimes (int p1, int p2) { printf ("%d and %d are twin-primes\n", p1, p2); }
The momentum can be cancelled when the objects are equal and opposite in momentum, 0= p1 + p2, thus p1=- p2. Newton's 3rd law.