superconductors
a superconductor
The formula you are looking for is W = E(squared)/R, W = Voltage (squared) divided by Resistance.
The formula for power is W = v2/R therefore the resistance is v2/W where v2 = v*v or v-squared. due to a font fault these formulas cannot be expressed correctly. But the answer to the question is R = 240*240/75 ohms.
The formula you are looking for is I = W/E.
In a DC circuit, the power dissipated by a resistance is (voltage across it)2 divided by 'R'.P = E2/R = (14.1)2 / 142 = 198.81/142 = 1.4 watts(rounded)
/* Input: Do Your Duty * Output: Duty Your Do */ import java.io.*; class RevSent { protected static void main()throws IOException { BufferedReader in=new BufferedReader(new InputStreamReader(System.in)); System.out.print("Enter the Sentence: "); String s=in.readLine(); char ch; short a=0,b=0; for(short i=0;i<s.length();i++) { ch=s.charAt(i); if(ch==' ') a++; } String w[]=new String[a+1]; for(short i=0;i<=a;i++) w[i]=""; for(short i=0;i<s.length();i++) { ch=s.charAt(i); if(ch==' ') b++; else w[b]+=ch; } for(short i=a;i>=0;i--) System.out.print(w[i]+" "); }}
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There are zero watts in 240 volts. To determine watts, an amperage or a resistance must be supplied. W = Amps x Volts, W = Amps (squared) x Resistance (in Ohms), or W = Voltage (squared)/Resistance.
w2-3w = 0 w(w-3) = 0 w = 3 or w = 0
No, w-w = 0. Any number minus itself is zero. On the other hand, 0 - w = -w.
49w2 - 25w = 0 factor out a w w(49w - 25) = 0 set the expression in the parenthesis to that 0 as w already = 0 49w - 25 = 0 49w = 25 w = 25/49 ============so w = 0 -------- w = 25/49 --------------
W. Nick Joseph has written: 'Resistance'
0%. Outer space is filled by Maxwell's Aether with "free space Resistance" z= W/Q =375 Ohms, where W and Q are electromagnetic Charges. Planck's Constant h=QW.
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The formula you are looking for is W = E(squared)/R, W = Voltage (squared) divided by Resistance.
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