Roman numerals
The answer is 174.DXXII/III = (C + LX + VI + II/III) + (III + I/III) + (III + I/III) + II/III = CLXXIVDXXII/III == D/III + X/III + X/III + II/III == (CxV)/III + (III + I/III) + (III + I/III) + II/III == Cx(V/III) + VII + I/III == Cx(I + II/III) + VII + I/III == C + (CxII)/III + VII + I/III == C + ((XxX)xII)/III + VII + I/III == C + Xx(XxII)/III + VII + I/III == C + Xx(VI + II/III) + VII + I/III == C + LX + (XxII)/III + VII + I/III == C + LX + VI + II/III + VII + I/III == CLXXIV
first 50 numbers of pi in roman numerals III. I IV I V II VI V III V VIII IX VIII IX III II III III VIII IV VI II VI IV III III VIII III II VII IX V NULLA II VIII VIII IV I IX VII I IX III IX IX III VII V I NULLA
III-II-LXXXXVIII or III-II-XCVIII or better still III-II-IIC because fewer numerals are used.
I, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, X
v iii ii you iv mean in numerals means v means 5 , iii means 3, ii means 2 and iv means 4.
The answer is 174.DXXII/III = (C + LX + VI + II/III) + (III + I/III) + (III + I/III) + II/III = CLXXIVDXXII/III == D/III + X/III + X/III + II/III == (CxV)/III + (III + I/III) + (III + I/III) + II/III == Cx(V/III) + VII + I/III == Cx(I + II/III) + VII + I/III == C + (CxII)/III + VII + I/III == C + ((XxX)xII)/III + VII + I/III == C + Xx(XxII)/III + VII + I/III == C + Xx(VI + II/III) + VII + I/III == C + LX + (XxII)/III + VII + I/III == C + LX + VI + II/III + VII + I/III == CLXXIV
Arabs developed the number system (0,1,2,3,4) we use now. The Roman system (I, II, III, IV, V) wasn't as good, because there was no zero.
4, it is a number expressed in roman numerals. in Roman numbering 1 - 10 is expressed like this: i ii iii iv v vi vii viii ix x
I'm going to assume ETP means electron transport proteins: The process would be glycolysis then Krebs then electron transport so yoru answer would be E
100% rudeeboiiiiiiii!iii!iii!ii!iii!iii!
first 50 numbers of pi in roman numerals III. I IV I V II VI V III V VIII IX VIII IX III II III III VIII IV VI II VI IV III III VIII III II VII IX V NULLA II VIII VIII IV I IX VII I IX III IX IX III VII V I NULLA
II and III only
III-II-LXXXXVIII or III-II-XCVIII or better still III-II-IIC because fewer numerals are used.
Leon Thomas II
What is the correct operational sequence of the three processes for I. glycolysis II. ETP III. rebsA I (r) II (r) IIIB II (r)I (r) IIIC III(r)I (r) II D II (r)III (r) IE I (r) III (r) II?Answer: E. I (r) III (r) II See Biology
Cobalt(II) carbonate
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