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Try Turing it off and back on again, if that doesn't work then you may hav to let it die to kinda "restart" it self
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∙ 11y ago
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Which of the following has a nostalgic connotation A longing B embrace C steamboat D calibrate?
steamboat
Why tan x graph is continuous within its domain and is not continuous out of the domain?
we do not check if a function is continuous or not outside it's domain."first, f has to be defined at c."Tanx is not defined where cosx=0 .ie x=pi/2 , 3pi/2 etcill try to help more here.what domain means is what can you put into a function, whereas range, which i am sure you have heard of as well, just means what you can get out of a function. that being said, lets look further into the graph of tanx. when we do, we see that the graph is discontinuous at pi/2. the reason for this is because tanx is equivalent to sinx/cosx. because of this relationship, when you put pi/2 in for x in sinx/cosx, you end up with cosx=0 which makes your denominator zero, which is undefined, which makes your graph discontinuous. because of that, you cannot put pi/2 in for x in tanx, and since the domain is what you can put into an equation, pi/2 which causes a discontinuity is not included in the domain. basicly, wherever a graph is discontinuous, it wont be included in the domain because you cant put stuff in that will make your graph discontinuous
What is x plus y to the second power plus z to the second power?
(x+y)^2+z^2=x^2+y^2+z^2+2xy or ((x+y)^2+z)^2= (x^2+y^2+2xy+z)^2= x^4+y^4+z^2+6x^2y^2+4x^3y+2x^2z^2+4xy^3+4xyz^2+2z^2y^2
What is the derivative of 1 over X square plus 2 with respect to X using the first principle?
I'm not sure if you're asking what the derivative is for f(x) = 1/[(x^2)+2] or for f(x) = [1/(x^2)]+2 so I'm gonna do the first one for now. Lemme know if you want the other one too! :)**Note: I'm not sure which terminology you're most familiar with using in class but just know that y is the same thing as/another way or writing y(x) or f(x) on the left side of the equation. Similarly, y' = y'(x) = f'(x) = d/dx(y) = dy/dx = d/dx[y(x)] = d/dx[f(x)].**So we know the First Principles from the Fundamental Theorem of Calculus defines the derivative as a limit:f'(x) = lim(h→0)⁡ [f(x+h)-f(x)]/hOur function is:f(x) = 1/[(x^2)+2]Similarly:f(x+h) = 1/[((x+h)^2)+2]Simplify:f(x+h) = 1/[(x+h)(x+h)+2]f(x+h) = 1/[(x^2+2xh+h^2+2]Then we plug it into the limit and simplify:f'(x) = lim(h→0)⁡ 〖[1/(((x+h)^2)+2)] - [1/((x^2)+2))]〗/hf'(x) = lim(h→0)⁡ 〖[1/(((x+h)^2)+2)] - [1/((x^2)+2))]〗*(1/h)f'(x) = lim(h→0)⁡ 〖[1/(((x+h)^2)+2)]*[(x^2)+2]/[(x^2)+2]- [1/((x^2)+2))]*[((x+h)^2)+2]/[((x+h)^2)+2]〗*(1/h)f'(x) = lim(h→0)⁡ 〖[[(x^2)+2]-[((x+h)^2)+2]]/[[(x^2)+2]*[((x+h)^2)+2]]〗*(1/h)f'(x) = lim(h→0)⁡ 〖[[(x^2)+2]-[(x^2+2xh+h^2)+2]]/[[(x^2)+2]*[((x^2+2xh+h^2)+2]]〗*(1/h)f'(x) = lim(h→0)⁡ 〖[(x^2)+2-(x^2)-2xh-(h^2)-2]/[[(x^2)+2]*[((x^2+2xh+h^2)+2]]〗*(1/h)f'(x) = lim(h→0)⁡ 〖[(x^2)+2-(x^2)-2xh-(h^2)-2]/[(x^4)+2(x^3)h+(x^2)(h^2)+2(x^2)+2(x^2)+4xh+2(h^2)+4]〗*(1/h)f'(x) = lim(h→0)⁡ 〖[-2xh-(h^2)]/[(x^4)+2(x^3)h+(x^2)(h^2)+4(x^2)+4xh+2(h^2)+4]〗*(1/h)f'(x) = lim(h→0)⁡ (2h)〖(-x-h)/[(x^4)+2(x^3)h+(x^2)(h^2)+4(x^2)+4xh+2(h^2)+4]〗*(1/h)f'(x) = lim(h→0)⁡ (2)〖(-x-h)/[(x^4)+2(x^3)h+(x^2)(h^2)+4(x^2)+4xh+2(h^2)+4]〗Finally, plug in 0 for h:f'(x) = lim(h→0)⁡ (2)〖(-x-(0))/[(x^4)+2(x^3)(0)+(x^2)((0)^2)+4(x^2)+4x(0)+2((0)^2)+4]〗 f'(x) = (2)[-x/[(x^4)+4(x^2)+4]Factor the denominator:f'(x) = (2)[-x/[(x^2)+2)^2]Final answer: f'(x) = -2x/[((x^2)+2)^2]Hope this helped!! ~Casey
What is integral tan3x sec2x?
-(4*log(2*cos(4*x)-4*cos(2*x)+3)-3*log(2*cos(4*x)+2)-2*log(2*cos(2*x)+2))/12
What do you do if no game will play in your leapster 2?
You need to reset your Leapster 2. Get more downloadable games for your Leapster 2 here: leapster-2.blogspot.com
Why won't my leapster turn on?
your leapster wont turn on because it probably needs new batteries and if that's not the case then it is probably broken.
Can the leapster 2 listen to music?
No you can't I'm afraid :-( Get more downloadable games for your Leapster 2 here: leapster-2.blogspot.com
Can leapster leapfrog 2 games be played on leapster leapfrog 1?
according to wikipedia 'All previous Leapster games play on the Leapster 2, and all Leapster 2 games play on a Leapster, though logged data can never be uploaded and any earned rewards unlocked.'
Does leapster old games work in leapster 2?
Yes, all leapster games are universal. They work in all the the leapster systems.
Is there a website for Leapster 2 game instructions?
You can get it from LeapFrog website of course :-) Get more downloadable games for your Leapster 2 here: leapster-2.blogspot.com
Is it worth upgrading from a Leapster 1 to a Leapster 2?
The Leapster is worth upgrading, with the Leapster 2 you have motion play and a built in camera, so extra bits for them to explore and learn further with.
What games can you buy for a leapster 2?
Instead of buying Cartridges in the shop, you also can get more downloadable games for Leapster 2 here: leapster-2.blogspot.com
Can you use leapster games for the leapster 2?
i think that yes you can save or watever in it
How do you download leapster to your computer from the disk?
You can download your Leapster 2 content from your console to your PC using LeapFrog Connect. But you have to setting your connection in LeapFrog Connect as below: 1. Go to Setting, and click Advanced tab 2. Make sure you tick ON for "Alternative connection for Crammer, Didj and Leapster 2" 3. Click APPLY 4. Eject your Leapster 2 from LeapFrog Connect. 5. Disconnect your USB connector from Leapster 2 6. Close the LeapFrog Connect application. 7. Re-connect your Leapster 2 to your PC. ... Source: leapster-2.blogspot.com PS: You can also download more games for your Leapster 2 there :-)
How do you delete all names on leapster 2?
I called leapster customer service to ask them the same question and they told me there wasn't a way to delete all names from the leapster 2.
Do you setup an sd card for a leapster 2?
Yes I did. I've to got SD Card for my Leapster 2 to make sure it works with 13 downloadble games that I got from here: leapster-2.blogspot.com
