copper2 nitrate
Cu(NO3)2 -----------Cu2+ + 2(NO3)-
2Na+ + 3CO- + Cu2+ +NO- = 2Na+ + NO3- + Cu2+ + CO-
Cu(NO3)2 pour le cuivre Cu2+ Cu(NO3) pour le cuivre Cu+
Zn(s) + Cu(NO3)2(aq) => Zn(NO3)2(aq) + Cu(s) Zn(s) + Cu2+(aq) + 2NO3-(aq) => Zn2+(aq) + 2NO3-(aq) + Cu(s) NET: Zn(s) + Cu2+(aq) => Zn2+(aq) + Cu(s
Cu2+ + 2AgNO3 --------> Cu(NO3)2 + 2 Ag+, due to high charge density for Copper ion as compare to Silver ion the reverse is not possible in aqueous solution.
Cu(NO3)2 -----------Cu2+ + 2(NO3)-
2Na+ + 3CO- + Cu2+ +NO- = 2Na+ + NO3- + Cu2+ + CO-
Fe2+ and NO3- ions will combine to form ferrous nitrate with the formula, Fe(NO3)2
Copper Nitrate -> has Cu2+ and NO3- NO3- won't touch other metals but Cu2+ will be displaced from solution, by ANY metal more reactive than copper. However, the speed of the reaction depends on many other factors. (Check the reactivity series on the internet) E.g. Na: 2 Na + Cu2+ => 2 Na+ + Cu (oxidation-reduction reaction, Cu as the oxidising agent) Examples of metals more reactive than copper (but might not react with Cu(NO3)2 immediately) are: Na, K, Fe, Zn, Al... and many many more
Zn(s) + Cu(NO3)2(aq) => Zn(NO3)2(aq) + Cu(s) Zn(s) + Cu2+(aq) + 2NO3-(aq) => Zn2+(aq) + 2NO3-(aq) + Cu(s) NET: Zn(s) + Cu2+(aq) => Zn2+(aq) + Cu(s
Cu2+ + 2AgNO3 --------> Cu(NO3)2 + 2 Ag+, due to high charge density for Copper ion as compare to Silver ion the reverse is not possible in aqueous solution.
Mg(NO3)2 1 magnesium atom, 2 nitrogen atoms, and 6 oxygen atoms Mg(NO3)2 because the charge on Mg is +2 and the charge of NO3 is -1 so you would need to balance. Magnesium has 2+ and Nitrate is one of the common polyatomic ions: NO3^1- Combine them both: Mg1(NO3)2 ===> Mg(NO3)2
Na, sodium, is in group 1 so it has a +1 charge. NO3, the nitrate polyatomic, has a -1 charge. So, they combine in a 1-1 ratio as NaNO3.
The ions Cu2+ and Cl-. Cu2+ + Cl- ---> CuCl2
Cu2+ + I- --> Cu2I The compound created is Copper(I) Iodide
The name of Cu^2+ or (Cu2+) is called: "The name of Cu2+ is _________ ion or ________ ion" 1st blank is: copper(II) 2nd blank is: cupric It is correct. i am a teacher.
Cu + Mg2 --------> Cu2 + Mg Cu --------------> Cu2 + 2e Mg2 + 2e --------> Mg Cu --------------> Cu2 + 2e (E = +0.35) Mg2 + 2e --------> Mg (E = -2.36V) +0.35 + (-2.36) = -2.01V --------------------------------------… Mg + Cu2 --------> Mg2 + Cu Mg --------------> Mg2 + 2e Cu2 + 2e --------> Cu Mg --------------> Mg2 + 2e (E = +2.36V) Cu2 + 2e --------> Mg (E = -0.35V) +2.36 + (-0.35) = +2.01V