A red-brown precipitate of copper acetylide is formed.
If chloride is present silver chloride with get precipitated..
there is no change
When you treat silver chloride with excess ammonia solution, Diamine silver (I) chloride is formed . The reaction involved is- AgCl + NH(3) --->Ag( (NH(3)) 2)(+) + Cl(-).What you will observe is that AgCl is insoluble, but after adding ammonia it becomes soluble because of above reaction.
When zinc nitrate solution is added to lead nitrate solution you willÊapparently observe a black solid being formed. All of the research yielded facts from adding solid metal to either zinc or lead.
There would be no reaction because astatine is less reactive than bromine.
If chloride is present silver chloride with get precipitated..
there is no change
The solution color of cupric oxide is blue to green.
The dihydrated salt is blue-green.
The white precipitate of silver chloride will dissolve when aqueous ammonia is added.
When you treat silver chloride with excess ammonia solution, Diamine silver (I) chloride is formed . The reaction involved is- AgCl + NH(3) --->Ag( (NH(3)) 2)(+) + Cl(-).What you will observe is that AgCl is insoluble, but after adding ammonia it becomes soluble because of above reaction.
solution
The melting point of sodium chloride is 801 0C.
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Should be a white precipitate. Indicative of the presence of either Na or Mg. Wrong again people. Silver Nitrate is used to test for the presence of chloride ions. Such as those in your salt a.k.a sodium chloride and yes adding silver nitrate to your salt solution will create a white precipitate.
When zinc nitrate solution is added to lead nitrate solution you willÊapparently observe a black solid being formed. All of the research yielded facts from adding solid metal to either zinc or lead.
The evidence that would lead you to believe that a residue was potassium chloride is it's white crystalline structure. When potassium chloride is mixed with water and the water evaporates, it leaves behind small potassium chloride crystals.