1444 Torr=1444 MM Hg
Converting 740 torr to mm Hg: 1 torr = 1 mm Hg so 740 torr = 740 mm HgTotal pressure = partial pressure O2 + partial pressure N2O (nitrous oxide, not nitrogen oxide)Pressure of N2O = 740 mm Hg - 370 mm Hg = 370 mm Hg
To convert Torr to mm Hg, divide by 1.33. So, the partial pressure of helium in mm Hg is 439 Torr / 1.33 = 330 mm Hg. To find the partial pressure of hydrogen, subtract the partial pressure of helium from the total pressure: 600 mm Hg - 330 mm Hg = 270 mm Hg. Hence, the partial pressure of hydrogen gas is 270 mm Hg.
All other factors being equal, the height of the column in a barometer is inversely related to the density of the material in that column. So we can write H = h (Rho/rho); where h = 745 mm Hg, H = ? mm in water, Rho = 13550 kg/m^3 Hg density and rho = 997 kg/m^3 water density. So we have H = 745*(13550/997) = 10125.12538 mm ~ 10.1 m when all other factors are equal. ANS.
It isn't. There is no unit of quantity in the SI system.Torr, historically was a unit of pressure, equal to one millimetre of Mercury. Equal nowadays to about 133.3 pascals.
760 mm hg = 0 psi gauge pressure
Converting 740 torr to mm Hg: 1 torr = 1 mm Hg so 740 torr = 740 mm HgTotal pressure = partial pressure O2 + partial pressure N2O (nitrous oxide, not nitrogen oxide)Pressure of N2O = 740 mm Hg - 370 mm Hg = 370 mm Hg
1 atm = 760 mm Hg = 760 torr = 101,325 kPa = 1,01325 bar
To convert Torr to mm Hg, divide by 1.33. So, the partial pressure of helium in mm Hg is 439 Torr / 1.33 = 330 mm Hg. To find the partial pressure of hydrogen, subtract the partial pressure of helium from the total pressure: 600 mm Hg - 330 mm Hg = 270 mm Hg. Hence, the partial pressure of hydrogen gas is 270 mm Hg.
Equals 101,325 pascals, 101.325 kpascals, 760 mm of Mercury, and/or 1 atmosphere
All other factors being equal, the height of the column in a barometer is inversely related to the density of the material in that column. So we can write H = h (Rho/rho); where h = 745 mm Hg, H = ? mm in water, Rho = 13550 kg/m^3 Hg density and rho = 997 kg/m^3 water density. So we have H = 745*(13550/997) = 10125.12538 mm ~ 10.1 m when all other factors are equal. ANS.
1 mmHg = 133.3 Pa Take your amount of mmHg and multiply it by 133.3 to get the number of Pascals. Take your amount of Pascals and divide by 133.3 to get the number of mmHg.
It isn't. There is no unit of quantity in the SI system.Torr, historically was a unit of pressure, equal to one millimetre of Mercury. Equal nowadays to about 133.3 pascals.
395.2 mmHGSimply put.1 ATM = 760 mmHG (Torr)0.520 * 760 = 395.2 mmHG
760 mm hg = 0 psi gauge pressure
500 mmHg or 500 torr is a gas pressure approximately 66% of the standard sea level air pressure of 760 torr ... it is the air pressure one would find at an altitude of approximately 3km or 10000 feet ... at sea level, 500 torr would be considered a partial vacuum of 0.66 atm.
521mm of mercury (torr) is 0.6855 atm
152 mm Hg is equal to 0,2 atmosphere.