n(1-R)L is an expression: it is not a formula.
This browser is totally bloody useless for mathematical display but...The probability function of the binomial distribution is P(X = r) = (nCr)*p^r*(1-p)^(n-r) where nCr =n!/[r!(n-r)!]Let n -> infinity while np = L, a constant, so that p = L/nthenP(X = r) = lim as n -> infinity of n*(n-1)*...*(n-k+1)/r! * (L/n)^r * (1 - L/n)^(n-r)= lim as n -> infinity of {n^r - O[(n)^(k-1)]}/r! * (L^r/n^r) * (1 - L/n)^(n-r)= lim as n -> infinity of 1/r! * (L^r) * (1 - L/n)^(n-r) (cancelling out n^r and removing O(n)^(r-1) as being insignificantly smaller than the denominator, n^r)= lim as n -> infinity of (L^r) / r! * (1 - L/n)^(n-r)Now lim n -> infinity of (1 - L/n)^n = e^(-L)and lim n -> infinity of (1 - L/n)^r = lim (1 - 0)^r = 1lim as n -> infinity of (1 - L/n)^(n-r) = e^(-L)So P(X = r) = L^r * e^(-L)/r! which is the probability function of the Poisson distribution with parameter L.
from the book title The Number 1 Ladies Detective Agency
from the book title The Number 1 Ladies Detective Agency
n : 2 l : 1 ml : -1, 0, or 1
(N-1)=(4-1)= N=3 l=0,1,2,3
If the sequence (n) converges to a limit L then, by definition, for any eps>0 there exists a number N such |n-L|N. However if eps=0.5 then whatever value of N we chose we find that whenever n>max{N,L}+1, |n-L|=n-L>1>eps. Proving the first statement false by contradiction.
Potassium has an electronic configuration of 1s2, 2s2, 2p6, 3s2, 3p6, 4s1 The azimuthal quantum number of 0corresonds to an s subshell, 1 p subshell You can see that you have n=1, l=0 n=2, l=0; n=2, l=1 n=3, l=0; n=3, l=1, n=4, l=0
it means "in a while"
Clean
I guess I should explain a little bit...l can take any integral value up to (n-1). So if n=1, l can only have one possible value- namely 0.l=(n-1)So if n=1, l is 0.If n=2, l is 0,1 0=s 1=p 2=d3=f
Emi = l * r * ((1 + r)^n / (1 + r)^n - 1) * 1/12 where l = loan amt r = rate of interest n = no of terms