I guess I should explain a little bit...
l can take any integral value up to (n-1). So if n=1, l can only have one possible value- namely 0.
l=(n-1)
So if n=1, l is 0.
If n=2, l is 0,1 0=s 1=p 2=d3=f
The third principal energy level (n=3) has s, p, and d sublevels. In the ground state, the zinc atom has all the s, p, and d sublevels in the n=3 energy level occupied. Therefore, the total number of occupied sublevels in the third principal energy level of a zinc atom in the ground state is 3.
In an argon atom, the outermost principle level is the third principle level (n=3). The sublevels that are occupied in this principle level are the s, p, and d sublevels. The s sublevel can hold a maximum of 2 electrons, the p sublevel can hold a maximum of 6 electrons, and the d sublevel can hold a maximum of 10 electrons.
The maximum is 18. This follows the law maximum = 2n2 where n = shell number, ie in this case n=3, 2n2=18.
The four sublevels encountered in the elements are s, p, d, f.The number of orbitals in each level are s, one; p, three, d ,five; f, 7.
In quantum number n=3, there are a total of 18 electrons. This is because the maximum number of electrons that can occupy the third energy level (n=3) is 2n^2, where n=3. Thus, 2(3^2) = 18 electrons can fill the n=3 energy level.
The third principal energy level (n=3) has s, p, and d sublevels. In the ground state, the zinc atom has all the s, p, and d sublevels in the n=3 energy level occupied. Therefore, the total number of occupied sublevels in the third principal energy level of a zinc atom in the ground state is 3.
In an argon atom, the outermost principle level is the third principle level (n=3). The sublevels that are occupied in this principle level are the s, p, and d sublevels. The s sublevel can hold a maximum of 2 electrons, the p sublevel can hold a maximum of 6 electrons, and the d sublevel can hold a maximum of 10 electrons.
In the third principal level (n=3), there are a total of 3 sublevels: s, p, and d. This means there are 3 orbitals in the third principal level of the atom: one s orbital, three p orbitals, and five d orbitals, making a total of 9 orbitals.
The fifth principal energy level (n=5) has a total of five sublevels: s, p, d, f, and g. Specifically, these correspond to the quantum numbers l=0 (s), l=1 (p), l=2 (d), l=3 (f), and l=4 (g). Therefore, the number of sublevels in the fifth principal level is five.
The maximum is 18. This follows the law maximum = 2n2 where n = shell number, ie in this case n=3, 2n2=18.
The four sublevels encountered in the elements are s, p, d, f.The number of orbitals in each level are s, one; p, three, d ,five; f, 7.
In quantum number n=3, there are a total of 18 electrons. This is because the maximum number of electrons that can occupy the third energy level (n=3) is 2n^2, where n=3. Thus, 2(3^2) = 18 electrons can fill the n=3 energy level.
1st energy has 1 sublevel -- 1 orbital -- 2 electrons 2nd energy level has 2 sublevels -- 4 orbitals -- 8 e- 3rd energy level has 3 sublevels -- 9 orbitals -- 18 e- 4th energy level has 4 sublevels -- 16 orbitals -- 32 e- Notice the pattern? number of orbitals = energy level squared Number of electrons = 2x number of orbitals
In the third principal quantum number (n=3), there are a maximum of 18 electrons that can be accommodated in different sublevels within that energy level (s, p, d).
The range of the levels is between 0 to n-1. 3 minus 1 equals to 2, so we have 0, 1, 2 as sub levels. They are the same number of sub-levels.
The number of sublevels within each energy level of an atom is equal to the value of the principal quantum number (n). Each principal quantum number corresponds to one sublevel within the energy level.
The valence electrons in an atom of nitrogen (N) are found in the 2s and 2p sublevels. There are a total of 5 valence electrons in nitrogen, with 2 in the 2s sublevel and 3 in the 2p sublevel.